MAT73
Chemical
- Feb 22, 2017
- 5
Hello again, and thanks in advance for clarifying the following question. Thanks in advance for your help and guidance.
Is the reason that the temperature in a liquid that is being pump increases due to the difference between the Break Horse Power of the Pump and the Actual Horsepower supplied by the motor and that amount of energy being "lost" as heat going into the fluid ?
Secondly, how could I calculate the expected rise in temperature (assuming that the liquid is water) if I know the flow rate coming out of the pump, motor HP and motor efficiency ?
Is the reason that the temperature in a liquid that is being pump increases due to the difference between the Break Horse Power of the Pump and the Actual Horsepower supplied by the motor and that amount of energy being "lost" as heat going into the fluid ?
Secondly, how could I calculate the expected rise in temperature (assuming that the liquid is water) if I know the flow rate coming out of the pump, motor HP and motor efficiency ?