Wind Load on Inclined Member

[StructuralAddict]

Hi, I have a quick question about the attached frame. The wind load is given as shown in the figure.

I want to calculate the reactions at the pinned and roller supports. What is the length that the wind load is applied at? Is it 15 ft or 9 ft? So, to get the resultant wind force, should I multiply 100 lb/ft by 15 ft or should I multiply it by 9 ft?

Thank you.

 

[r13]

On the project area, that is normal to the direction of wind.

 

[KootK]

For component and cladding situations, I believe that the wind should be assumed to act perpendicularly to the surface to which it is applied.

 

[KootK]

To answer your specific question, assuming the load to be a projected load as you"ve drawn it, you would multiply the load by the 9' distance to get the total load. Multiplying by the 15' distance would really imply the creation of new load that wasn't there to begin with.

 

[BAretired]

Your question may be quick, but the answer is not.

The wind pressure corresponding to 100 on a vertical surface does not correspond to 100 on a sloping surface. You would need to consult wind charts in the code for the appropriate pressure which would then be applied normal to the sloping surface and would be multiplied by 15, not 9.

Your slope is 37^o, so the normal pressure is only about 40 or 50 which should be multiplied by 15 to get the normal force, but depending on the location of openings, there could be an internal pressure acting simultaneously. With windows on the leeward side, the internal pressure would be negative, which would add to the positive pressure on the outside.

BA

 

[StructuralAddict]

Thank you @retired13 , @KootK and @BAretired for the information you provided.. I appreciate it!

 

[r13]

You are welcome. Just make sure you position the wind pressure in correct direction to generate the most undesirable situation, after that, it's all simple statics.