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Worm Axial force

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solitzer

Mechanical
Jan 12, 2005
3
US
Can somebody please tell me how to calculate the axial force of a worm with a given RPM, torque, and worm specifications.

 
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solitzer,

A very simple way is as follows:

F = 63025 * HP / rpm * p

Where:

F = Axial force on worm
rpm = rpm of worm
p = pitch radius of worm
HP = Motor horsepower

Haggis
 
Please pardon my ignorance, but would this be the output force that would be transferred from the worm to the worm gear?
 
I don't think solitzer is quite right. The units of his equation are in#in. A good approximate equation is that the axial load, F = Torque/2 * 1/R * 1/(tan(LA)). For example, if torque = 7.5 in#, pitch radius = .312" and the lead angle is 6 degrees, the axial force would be 114#.
 
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