Worst Case Tolerancing

[FM44]

Hi,
Can any one, please, answer the following question in laymen terms:
- if I am doing a simple "worst case" tolerance analysis, how many pairs of the extreme dimensions do I consider?
example:
I have a pair of bayonet hooks (plastic part), which are 2.00 inches apart.(with +/-.01 tolerance.
The mating hooks are 2.01 inches apart (with +.02/-0 in.)
Which worst cases and how many pairs am I supposed to consider.
should they be as follows:
Max Bayonet-Min hook= x1
Min Bayonet-Max hook=x2
Min Bayone-Min hook=x3
Max Bayonet-Max hook=x4

Are these enough combination?
Please help!
thank you.

FM

 

[monkeydog]

Max Hook (2.00 + .01)- Min match (2.01-.00)
Min Hook (2.00 - .01) - Max match (2.01 + .02)

Not accounting for location of the hooks, as you described, this is only the dimensional between the hooks.

 

[FM44]

monkeydog,
I appreciate your help.
From this point onward, I am assuming, I should pick such a range of tolerance that there will always be some clearance between the mating features.
Right?
Thank you.

FM44

 

[vims]

Right.

 

[monkeydog]

Yes, if clearance is what you want.
ANSI Y14.5M is the governing document on tolerancing, but there are other books on the subject.

 

[FM44]

monkeydog/vims,
Thank you for your help. Even though the assembly is more complicated and I just presented it in simplest terms, just to understand the basics. I should be able to take it from here.
I appreciate your time and help.


Farid