Yield strength conversion to shear strength. 4

[FranLopez]

Blueprint called out for material corrosion resistant steel A286 per AMS5732with a 95,000 PSI minimum shear strength. The material Cert shows only Yield strength: 121,000 PSI and Tensile strength: 161,000 PSI.

The mill company said AMS 5732 does not call for shear strength. I dont have the spec, and It would take a day to get one. what is the formula to convert Yield strength to Shear strength? or would be better to send the material for shear strength test anyway?

 

[dhengr]

Fran:
When I look around on this topic here’s what I come up with: The yield stress in shear is approx. its theoretical value of Fy/[sq.rt.(3)] = .58Fy or .58 times the yield strength in tension, this comes from the Hencky-von Mises yield criteria; and tests usually indicate the ultimate shear strength ranges from 2/3 to 3/4 of the ultimate tensile strength. When you order the material find out what the mill or supplier provides in the way of testing with its mill certs. Many times you can negotiate with them and get them to include other tests on the certs., for some extra cost, of course.

 

[rb1957]

i think there's a disconnect between the ASM spec (85 ksi) and the drawing reqmt (95 ksi) ... which sort of punts my diatribe into left field !

on-spec material doesn't meet the drwg reqmt, so you need to do the additional test. given that FTU is 160ksi (spec = 130ksi), i'd expect that you'll get your 95 ksi Fsu.

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