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Can you weld something that does not have a workable flat per AISC? 3

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SeizeTheMoment

SeizeTheMoment

Structural
Sep 16, 2020
25
Say for example you have a HSS2x2x1/4 beam connected to a HSS2x2x1/4 column. The delegated designer is saying to weld these two together with a 3/16" fillet weld all around. A HSS this size does not really have a workable flat, so I'm not sure if this really works. On a second note, does anyone have a reference for finding the section moduli for something like a HSS which would have rounded corners?

Don't bend to the stress, seize the moment!
 
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Regarding the welding, have a look at your local welding code, they should have prequalified welds for joining two SHS like you want. I think what they really mean is ensuring a similar throat thickness to a 3/16" fillet weld, that's really what matters. My local code for example has something like this showing it is indeed possible to weld:-
Screenshot_2022-11-12_001551_rjqulg.png



As for properties:-
Screenshot_2022-11-12_001026_dugar4.png

Screenshot_2022-11-12_001044_ervdp9.png


 
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Thanks Agent... excellent info; I'll check the formulae with the ones I use in my SMath program and some additional ones. One of the nice things about SMath, is that I can do a Windows snapshot of the formulae, and past it 'off page' in SMath. I calculate the weld areas by adjusting for the sloped surface.

-----*****-----
So strange to see the singularity approaching while the entire planet is rapidly turning into a hellscape. -John Coates

-Dik
 
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Thanks Agent. I agree with the fillet weld just being the minimum effective thickness, flare bevel at the edges of the HSS would have a thicker effective size than the fillet. I was trying to figure out the section moduli using Blodgett's method, but looking at AISC it looks like we have something similar:

Screenshot_2022-11-11_121817_kw7hbf.jpg


Don't bend to the stress, seize the moment!
 
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On the rounded side it's not a fillet weld. More like a flare-bevel.
 
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@JLNJ yes I agree. Fillet weld would have 0.707 x 3/16" = 0.132" effective throat, while the flare bevel would have 5/16 x 2(1/4") = 0.16". The flare bevel is technically larger, so I think that's why calling out a fillet weld all around would work in this case (but if we want to be correct, then yes it should be flare bevel).

Don't bend to the stress, seize the moment!
 
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Agent, are the values for the corners:

Clipboard01_tnir2z.jpg


-----*****-----
So strange to see the singularity approaching while the entire planet is rapidly turning into a hellscape. -John Coates

-Dik
 
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