I am trying to simulate a frame where the beams are connected to the columns via hinges. I have it working as rigid connection but I do not know how to add releases for the moments.
Hey everyone,
I'm a Canadian citizen about to finish my master's in structural engineering. I've already passed both the FE and PE exams (Oregon lets you take the PE early) and I'm registered as an EIT in Texas. My goal is to work in the U.S., and I'm planning to apply for jobs there directly...
Hello I am doing a design project for school. I am designing an office building, all the structural components have to be made from wood. I plan to design CLT shear walls for the LFRS, and I want to use conventional 2x4 stud framing for the reminder of the exterior walls to only carry vertical...
Hello I am trying to create a semi-stiff connection between 2 nodes but having difficult.
Currently I can simulate a fixed connection by using the beam connector, and a pinned connection by using JOIN+ROTATION connection type. However I want to implement a semi stiff connection.
Just something...
Hello, I have a question, according to ASCE 7 12.3.1.3 a diaphragm can be idealized as flexible if maximum diaphragm deflection is greater then 2 times average story drift. Assuming my building has multiple shear walls as its LFRS. I can calculate the story drift by finding the vertical...
It’s always P/A-Mc/I, you take M as positive or negative following the convention in the PE handbook, and c is positive or negative depending on if the fiber you are looking at is above or below the centroid.
In the reference handbook the formula for sigma should be sigma = -Mc/I, as long as...
I just want to clear confusion, yes there are those circles but this question doesn’t mention rebar. I think they just used a bad image for the question but just do not worry about the rebar.
Also the thank you Celt83, you helped clear up my understanding.
Can you relax, I knew the concept just forgot the name of it. Your response isn't helpful at all. I was just confused due to the wording in the PE Reference Manual
The NA is where the stress in the cross section = 0. If we take the formula sigma = P/A - My/I and set it equal to 0
P/A - My/I = 0
M = Pe
then we can find that
y = I/(Ae)
This y would be where the NA axis is located with reference to the centroid. Because this is where sigma = 0, and the...
In the PE Reference Handbook Section 1.6.7.2 they define c as distance from NA.
The NA axis is shifting due to a axial load being applied with a eccentricity.
Hello I was doing a question in order to prep for the PE exam and I ran into this problem which I got wrong.
In this question since the cross section is being loaded axially plus a moment due to the eccentricity, that the neutral axis will shift from the centroid location. However in the...
