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  • Users: w1999
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  1. w1999

    Condensate Return/ Pump Capacity/ Head

    Thank you TBP for these info. You the only one who got back to me. I am still new in Engineering Field, "Steam", etc. Thank you again.
  2. w1999

    Condensate Return/ Pump Capacity/ Head

    No, there is no hot water HX. The bldg. is 80'x64'. The total steam load to the bldg. 480 #/hr for (3)48#/hr UH, (1)18#/hr UH and (1)314 #/hr for HV unit. The HV unit has 5120 CFM, face velocity=640 fpm, Entering DBT=15 F Leaving DBT=72 F Steam Temp.=227 F Thank you for your help.
  3. w1999

    Condensate Return/ Pump Capacity/ Head

    Hello TBP, 1 GPM all I need, what about delta T. 1 GPM=(500#/hr)/500, (500=8.3lbs/gal*60 min/hr) GPM=(500#/h)/(20 F*500)= 500*975 BTUH/10000=48.75 GPM How about the lift, (600'+300')for fitting, elbows*0.04=36 feet. Best regards.
  4. w1999

    Condensate Return/ Pump Capacity/ Head

    Hello All, Please I need your help. I have a LP-steam boiler discharge preesure 10 psig, located 600 feet from a building. The pressure entering the bldg. 5 psig. I allow 5 psig pressure drop for the run, and 5 psig to the bldg. The bldg. area 5312 sq.ft and the total steam load 480 #/hr for 3...
  5. w1999

    Pump head formula

    Thank you lilliput1 for this formula, and all variable details.
  6. w1999

    Pump head formula

    Thank you all for these inputs and help.
  7. w1999

    Pump head formula

    Hello all, I am new in engineering field, I was loking for a formula to find a pump head, I found one: Head=total pipe length*50% for elbows and fitting * 0.04. The last term I did not know what represent. I know the formula for head is:V sq/ 2g. Please, does any one can tell me what the 0.04...

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