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Hi MintJulep, I really appreciate the nuggets of information but I'm not sure how exactly to apply this to my calculation. The only other relevant thing I found online was the following, but I'm still unsure how to use this too: The taper is a wedge with angle α, that converts bolt axial force...

Ok, great info, here's another stab at the math: Arm/Lever torque around pivot point: 18 (kg) x 0.17 (mm) x 9.81 (m/s2) = 30 Nm Bolt Clamp force: Bolt torque 5 (Nm) / Bolt diameter 0.01 (m) x CofF 0.2 = 2500 N Average radius = 13 mm Number of braking faces = 2 Torque from braking mech...

Also this is where I got the clamping formula from: https://www.engineersedge.com/calculators/torque_calc.htm

Thanks for the feedback. What is the correct formula/approach to figure out the needed torque/clamping force to hold the weight? Hopefully the image below helps

Hi guys, I am trying to design a brake/locking mechanism to hold up a weight, here is some background; I have a weight 18kg, 170mm away from the pivot point on an arm. A brake compresses the arm at the pivot point. This consist of a M10 bolt compressing a surface area of 1500mm^2 on each side of...

Please ignore "counterbalancing effect no matter the angle". I am looking to find what force is needed by the spring to keep these two weights horizontal to the pivot point. Thank you

Ah ok I can see I did a bad job of explaining my issue. The CAM and Spring in this design are easily designed to give a counterbalance effect. What I' more concerned about is calculating the correct force is on the spring if we just look at static horizontal position. So I was looking to find...

The Slot/CAM profile is needed to balance the spring compression at different angles - giving more or less force as required to give a counter balancing effect no matter the angle. Where do you see the issues here? please be specific. Also do you see anything wrong with the maths? See below CAD...

Hi everyone, I'm creating a mechanism to lift a weight and I need to make sure I'm calculating correctly in order to design the correct spring. The first image below shows you my current design, but I have realized that there is a lever action here that could drastically increase the force on my...