Yes you missed another Fy force at the blue bar which force will be located at the torque gun position.
The two Fy forces you then have are parallel to each other and work in opposite direction.
They will create a torque equal to the torque of the gun but in opposite direction, so -20Nm
So then...
That' a small shaft for a taper bushing! As an alternative you could split the brass flywheels in two equal pieces right through the shafthole.
Consider using a lasercutter for that to keep the cutting width as small as possible.
Then clamp the two halves together with screws and nuts/threaded...
Hi Gary,
I can do this for you. Doing mechanical engineering in 3d cad as well as FEA simulation and detailing for production. Based in the Netherlands.
Using dropbox or wetransfer cooperation with Scotland is no problem.
To clarify my first post: Shorten link 3 so that both cranks 1 and 2 are perpendicular to link 3. That position will be the center position of the mechanism from where it can swivel left and right.
You can certainly achieve complementary rotation angles of the two shafts but only when these angles are symmetric around a plane perpendicular to where bar 3 is tangent to the two crank radii.
So the start/stop angles 195, 315 and 45, 165 will change then.
If that is acceptable there is a...
If the two bolted faces can be assumed staying planar completely up to the bends towards the 1.52 long face and moving apart each in line, then the answer to question 2 can be found using elastic beam analysis.
Since the part is symmetric I suggest to do such analysis only on the top half and...
Hi Douggroh,
In dough sheeting lines it is common practice to add a horizontal movement to the guillotine knife in sheet running direction. This happens at sheet speeds from 1 m/min up to 15 m/min so 4 m/min should be no problem at all. The only difference between these guillotines and yours is...
based upon F=1500lbs to stretch 1% and a roller to roller distance L(length) = 144" the beltpart stiffness is 1500 lbs/1.44" or 1041 lbs/inch or 182 N/mm'
I suggest to check the deflection of the roller first at 1 promille stretch which means 2 times a pretension force of 150lbs per beltpart or...
This case is similar to what I experienced more than once! The lower the pretension the better it is for the construction and rollers/bearings. The value of 22lbs/inch (width) is a safe factor for the supplier which will work in many applications. However the belt supplier is not building the...
Usually the belt pre-tension is listed in the belt suppliers spec sheet (at least for Pu belts with fabric layer(s) inside).
So look at the cotton belt specs for a value like x newtons per mm belt width or similar.
That pretension value is based on experience and will suit most applications to...
Hey thejack473,
After reading your post and watching the videos I suggest to try avoiding pin/slot mechanisms for this since it will be difficult (nearly impossible) to keep hertz stresses acceptable under a 200kN load. I suggest investigating a bar linkage mechanism like the hydraulic scoop...
In our company we have a rule that, in order to avoid a machine tipping over, the COG always need to be within a triangle with a top corner 40 degrees and a basis equal to the footprint width of a frame. Footprint width is mostly the machine feet pitch distance in our case. So theoretically one...
Hello vinerunner,
You talk about a removable hub. So play between the hub and the square shaft is a given I would say.
Given that play a torque would try to rotate the hub at the shaft resulting in a maximum of 4 pressforces close to the shaft corners.
But based on dimension tolerances it is...
No, fixing all four supports is not what I mean. I suggest fixing the crane frame in a location as close to its C.O.G.
Then only add a collision force at one leg.
Then simulate and conclude what deflections and stresses that one leg will show.
Your method of adding orthogonal rods will also...
yes, that's the way i simulate such situations: constrain the entire body and than add a force to the leg against the direction the body moved
then simulate and find out xyz deflections and 3 rotations of the leg
So look at this problem as if the crane is in rest and a object hits that one leg
Besides my comment above I suggest that you look into the specs of the cells and also how they are connected to the construction. Many loadcells can handle pull as well as push forces. So it might be possible that you can skip the idea of adding air cylinders completely.
