Hi David,
Correct me if I'm not right but should that formula be P1=P2(m1/(m1+mgas)) rather than P2=P1(m1/(m1+mgas))? If not then that would mean that P2<P1
Thanks
Thanks for the reply.
The type of filter I'm talking about is a bag type filter, with the filtrate outlet built into the floor of the filter housing. Therefore, from your description it sounds like my dead volume is negligible.
So dividing the volume of gas emitted in litres by the free headspace volume in the vessel would be an incorrect way to work out the pressure increase in barg?
There is a liquid in a reactor and the headspace is occupied by nitrogen. The gauge pressure in the headspace is 0barg. If the liquid then emitted a known quantity of e.g. CO2 into the headspace how would I work out the pressure increase in the headspace?
All,
I was wondering if anyone would be able to recommend suitable software for calculating of process reactor abatement emissions, for different activities within the vessel i.e. heating, pressurisation etc. (assumming the vessel has certain reagents/solvents contained within. Basically I want...
Thanks for taking time to reply.
I understand that different pumps can give much different flowrates even though the pressures may be similar. However if the pressures are similar and if the head is also similar then is this not where the pump curve for the specific pump in question comes into...
Thank you everyone for taking the time to respond, much appreciated. I've been reviewing your comments and doing a lot of reading on the different types of head (static,dynamic, elevation)in relation to pumps, so as to develop my knowledge. I was wondering if anyone could help me again with the...
The energy provided by a pump is measured in terms of head. This is independent of the liquid density. How would you prove this from a mathematical point of view. The formula for static head has a density term in it. So then how could head not be related to density. Any help clarifying this...