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i believe there is 2 versions of the book. Si and english

Thank you for the advice. Yes, directly under the angle is the bolt plate that was for the leg.

The above picture is what my engineering manager told me to do. I went to him and told him i wasnt comfortable removing the leg, he said to add that cantilevered weldment shown above and told me that was it. He told me that "no body" calculates platforms and that i was wasting my time. I said...

See attachment, This is what i have decided to do. It will be welded into place. Thanks fox, i appreciate it!http://files.engineering.com/getfile.aspx?folder=6a9e404f-02c5-4351-9aca-d556dad8686c&file=Pheonix-AB.JPG

Thanks for the replies, I was also thinking since this machinary is in the plant. I can have them weld the platform to the tubing and lose the bolts. It was bolted for shippig. I have that book! i just recently bought it cause it was recommended. I love it! got a lot of good information. I...

See new attachment. The PDF has 2 pages. I hope that it shows more of what is happening. Thanks for the help foxhttp://files.engineering.com/getfile.aspx?folder=838e8d8b-8987-460a-945a-25c574e25638&file=Pheonix-AB.pdf

Desert fox, Yes, that is correct. Boxed leg is the one they want to remove. You are saying uniform is the same as taking my load at 37" out? I was thinking it would be half that cause the average would focus in the middle of the frame. --------------- Keep in mind, i am adding self weight...

In the diagram i was representing a uniform load of 2188 * 10 SF. How would i calculate this in a unform load?

Sorry, the angle that is facing the right side that has 8 red bolts in it, that is bolted to a frame. That frame is made of 4 x 4 x 1/4" tubing. That is what is holding this platform along the entirity of the angle. Desertfox I went to your diagram used on that other forum. I couldnt find where...

I have an application that i have been trying to use calculations from a different post http://www.eng-tips.com/viewthread.cfm?qid=262972 and am having some trouble. I have a customer that is wanting to remove a leg from their platform to allow for a conveyor to travel under it. See attached...

Id start searching mc msster as a refrence, see if they got something you could use.. Then from there find the actual manufactures of the springs so ur not paying an arm and a leg

It doesnt run in reverse ever?

I see you put slots in the counterpart that can allow for misalignment. Im susupecting this isnt a very fast system?

It needs to lower at a slow rate? I wonder if you could use something that hangs and acts similar to an oil shock only in reverse.. So the reservoir can be positioned above the surface, and the rod eye or steel clevis and rod is the only thing that lowers into the oil.. Maybe using extension...

They are very simular to gas springs

When I take into consideration of impact loads, i take a stopping time of 1/20th of a second.. so it decels from whatever volocity to zero in 1/20th of a second.. like if u dropped a hammer on a concrete floor the floor would see a load of - if the hammer was to be 5lbs and drops at 16ft/s...

These drums will be on gravity conveyor that will be at a few degrees.. guys will push it onto a powered chain conveyor.. As you see I want the pin to come up and hold one drum. Then it will pivot back and stop the 2nd drum behind that position. Then it will pivot back to allow it to come to the...

Still incomplete but as you can see the drum will run into the pin stop. It will put pressure on the bushings on the bar links that I have. I want to ensure I'm not putting too much pressure to damage the bronze bushings I'm using for...

Thats interesting however my force isn't created by rotation, I guess I should have put side load. If I were to put force on the shaft to the side what would be the appropriate way to calculate the compression on the bushing?

If I am making a bar link system and I use bronze bushings on the pivot points. If I put force on the shaft momentarily against the bushing (impact load - while link is stationary), how do I calculate the allowable pressure on the bushing area? I have in the past taken half the circumference of...