Pickaspot
Mechanical
- Jan 31, 2015
- 5
ASME Section IX
QW-452.1
Thickness of weld metal qualified
Production application 1/2" NPS (.840" OD) schedule 80 (.147" wall)open butt groove weld (GTAW out)P4 to P8.
WPQ qualified with volumetric NDE, welder produced 3qty. 1/2" schedule 80 coupons meeting the 6" (QW-302.2)section IX requirement in the 6G position utilizing GTAW out.
My question specifically is in regards to QW-452.1(b)Note(2)which states:
Two or more pipe test coupons with different weld metal thickness may be used to determine the weld metal thickness qualified and that thickness may be applied to production welds to the smallest diameter for which the welder is qualified in accordance with table QW-452.3.
For some reason....my interpretation of note(2)is that this would actually give the welder a thickness qualification range of .882"?
I have asked some of my colleagues, one agrees and two disagree. For the two that disagree their interpretation is that if the welder welds the 1/2"nps (.840"od)(.147" wall) coupon and a 2"nps (2.375"od)sch80 coupon (.218" wall)the welders thickness qualified would be (.436" max)with reference to note(2)I see it as being .73" qualified thickness?
Back in my rod burning day's I took several small diameter test's (boilers)as stated above producing 3qty 1/2" coupons for RT. Why would most implement the two additional 1/2" coupons when all they would need is one 2"nps coupon as a result achieving the 6" requirement and adding to the thickness qualified while reducing test time, cost and difficulty for the welder?
Does anyone else interpret note (2) the same or am I just nuts? LOL!
QW-452.1
Thickness of weld metal qualified
Production application 1/2" NPS (.840" OD) schedule 80 (.147" wall)open butt groove weld (GTAW out)P4 to P8.
WPQ qualified with volumetric NDE, welder produced 3qty. 1/2" schedule 80 coupons meeting the 6" (QW-302.2)section IX requirement in the 6G position utilizing GTAW out.
My question specifically is in regards to QW-452.1(b)Note(2)which states:
Two or more pipe test coupons with different weld metal thickness may be used to determine the weld metal thickness qualified and that thickness may be applied to production welds to the smallest diameter for which the welder is qualified in accordance with table QW-452.3.
For some reason....my interpretation of note(2)is that this would actually give the welder a thickness qualification range of .882"?
I have asked some of my colleagues, one agrees and two disagree. For the two that disagree their interpretation is that if the welder welds the 1/2"nps (.840"od)(.147" wall) coupon and a 2"nps (2.375"od)sch80 coupon (.218" wall)the welders thickness qualified would be (.436" max)with reference to note(2)I see it as being .73" qualified thickness?
Back in my rod burning day's I took several small diameter test's (boilers)as stated above producing 3qty 1/2" coupons for RT. Why would most implement the two additional 1/2" coupons when all they would need is one 2"nps coupon as a result achieving the 6" requirement and adding to the thickness qualified while reducing test time, cost and difficulty for the welder?
Does anyone else interpret note (2) the same or am I just nuts? LOL!