According to IEC 60909 ch.3 Three-phase overhead lines the inductive reactance (XL) for symmetrically twisted single-circuit and double-circuit lines are:
Single-circuit XL=w*miuo/(2*pi())*(ln(d/re)+1/(4*n)) in ohm/km
Double-circuit XL=w*miuo/(2*pi())*(ln(d*d'/(re*d"))+1/(4*n)) in ohm/km
where :
w=2*pi()*frq [frq=50 or 60 Hz]
miuo=4*pi()/10^7 H/m
re=equivalent conductor radius[mm] re=at/(2*sin(pi())/n) [approximately]
at=distance between 2 conductors on the last layer[mm] usually the aluminum conductor diameter and n=no. of strands in a bundle.
But for ACSR this is not accurate enough.
If we use this formula XL=2*PI()*frq*miuo/2/pi()*ln(d/re) then according to:
August Hochreiner "Symmetrische Komponenten im Drehstromsystemen" Berlin 1957 [see:
]
who gave experimental results as follow:
ACSR with 26 AL cond. in 2 layers re=0.809*r where r is the actual conductor radius.
ACSR with 30 AL cond. in 2 layers re=0.826*r where r is the actual conductor radius.
ACSR with 54AL cond. in 3 layers re=0.810*r where r is the actual conductor radius.
That is very close to GMR given by manufacturer catalog produce in USA [B232]
IF fqr=50 Hz then XL=0.06283*LN(d/re) ohm/km d and re both in the same units [mm or m]