jrafael95
Mechanical
- Feb 2, 2020
- 17
Dear all,
im designing a tank under api 650 annex F for academic purpose.
the roof is cone type (self-supporting) with 9.5º slope
Using the equation given in F.6.1 (written below) i got 0.046 mm
t = (P x R)/((cos(alpha)*Sd*E) + CA
t = (0.363*2.865)/(0.165*137*1) = 0.046 mm
here is my data:
Intenal pressure (P) = 0.363 kPa
Nominal Radius (Rt) = 2.865 m
alpha = (180 - 2*9.5)/2 = 80.5º
allowable stress (Sd) = 137 MPa
Joint eff (E) = 1
Im using API 650, 12th Ed.
Thanks for answers !
im designing a tank under api 650 annex F for academic purpose.
the roof is cone type (self-supporting) with 9.5º slope
Using the equation given in F.6.1 (written below) i got 0.046 mm
t = (P x R)/((cos(alpha)*Sd*E) + CA
t = (0.363*2.865)/(0.165*137*1) = 0.046 mm
here is my data:
Intenal pressure (P) = 0.363 kPa
Nominal Radius (Rt) = 2.865 m
alpha = (180 - 2*9.5)/2 = 80.5º
allowable stress (Sd) = 137 MPa
Joint eff (E) = 1
Im using API 650, 12th Ed.
Thanks for answers !