(Applied Thermodynamics)__How to calculate the specific volume of water, at 100ºC and 1.5 bar? 3

[Nerdy123456]

The only data in the question is this table:

Do we have to do an interpolation between the point at 100ºc + 1.014 bar, the point at 110ºC+ 1.433 bar, and the point at 120ºC + 1.985 bar ?

What other suggestions you may have?

Thanks a lot!

 

[monkeydog]

Look here:

http://webbook.nist.gov/chemistry/fluid/

 

[Latexman]

I'd use 1.0435x10[sup]-3[/sup] m[sup]3[/sup]/kg from the sat'd 100[sup]o[/sup] C liquid. The change in density/specific volume on a liquid (water) by compressing it from 1.014 bar to 1.5 bar is nil.

Good luck,
Latexman

To a ChE, the glass is always full - 1/2 air and 1/2 water.

 

[Nerdy123456]

Thanks guys!!

 

[Latexman]

NIST gave sat'd properties density = 958.35 lb/m[sup]3[/sup] and 1.5 bar isobaric properties density = 958.37 lb/m[sup]3[/sup].



Good luck,
Latexman

To a ChE, the glass is always full - 1/2 air and 1/2 water.

 

[quark]

Steamtab
You need not look in to a table, again, once you download this.

 

[25362]

From NIST webbook. 0.0010434 m[sup]3[/sup]/kg.

 

[chicopee]

An alternate method is to use a steam Mollier diagram since it will show the specific volume lines in the superheated region. You may have to interpolate and loose a little accuracy.