Applying kinetic energy to a circular hollow section

[HungryDinosaur_imported]

Hi All,

I have some value of kinetic energy, 1.82 kN.m which I want to apply to a steel circular hollow section member Dia. 140mm x 10mm thickness, 5m length.

I want to apply this energy as a force. Is there a way I can apply this?

Regards,

HD

 

[IRstuff]

What exactly is the intent? As written, your question doesn't make sense.

Force = m * dv/dt
KE = 1/2 * m * v^2

Force is therefore related to the rate of KE applied; you can apply it in a nanosecond, or in seconds.

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[zeusfaber]

Assuming that by "as a force" you mean you want to impart the energy mechanically as opposed to heating it up with a torch, etc.

Drop a piano on it from a height of about a metre?

 

[BUGGAR]

That sounds like some kind of a fender system?? And you are looking for the equivalent of the fender reaction? You will have to figure the pipe deflection mechanics to get a force-deflection graph. Then see how much the pipe has to deflect to absorb your energy and determine the resulting elastic/plastic reaction force at this deflection.

 

[IRstuff]

1.82 kN-m = 1820 J

Near as I can guess, that could be a 7.62x51mm round traveling at 600 m/s

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[HungryDinosaur_imported]

Thanks for all the answers. This KE is from a traveling object that will hit the steel circular section, with a energy of KE = 1/2 * m * v^2, which comes out to be around 1.82 kN.m.

 

[IRstuff]

You could have started with that; it would have saved a day. Nevertheless, you also need the velocity.
> Are you trying to do this IRL?
> What are the materials involved? - marshmallow traveling at 600 m/s will have different impact characteristics than lead, or steel, or depleted uranium. Material of pipe needs to be known
> Are you trying to determine puncture resistance?

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[GregLocock]

Well that was agony. I assume we are now talking about a ship or whatever smacking into a pile or drill shaft.


Cheers

Greg Locock


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[IRstuff]

Not with 1820-J KE...

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[HTURKAK]

You have provided very limited info. What is the position of cantilever ( vertical or horizontal ) ? What is the material of the travelling body and mass ? The energy 1.82 kN-m can be obtained with different mass and velocity combinations..the peak contact force depends on several factors...pls provide some clues to get answer.