ipi
Petroleum
- Nov 24, 2004
- 25
Hello all;
I was reading the below link for thickness limitation w.r.t "t+6mm" maximum limitation as given in A5 of B31.3 table 323.1 (Prior to 2020 edition)
Now this requirement(t+6mm) is removed in 2020edition, it is being interpreted as 2T thickness(ASME Sec.IX) instead of T+6 mm.
Iam some what confused. should it not be interpreted as T+0mm since T + 6mm is removed?
Consider for Eg a "Curve A material" B31.3 with reference MDMT 0C
The PQR thickness is 14.3mm whose MDT is 2.8C(table 323.2.2A B31.3) and hence impact tested @ 0C.
How can this qualify for 28.6mm whose MDT as per the above table is 23.6C? for MDMT 0C?
How can 2T qualification be logical?
Shouldn't T+0(or 14.3mm) is the maximum qualified???
Thanks in advance for your inputs
Edit 1:-
In addition to above does not the thicker material is more prone to brittle fracture?. So if ASME sec. 9 restricts the minimum qualified, is it not relevant that the thicker material tests be more stringent?
I was reading the below link for thickness limitation w.r.t "t+6mm" maximum limitation as given in A5 of B31.3 table 323.1 (Prior to 2020 edition)
Now this requirement(t+6mm) is removed in 2020edition, it is being interpreted as 2T thickness(ASME Sec.IX) instead of T+6 mm.
Iam some what confused. should it not be interpreted as T+0mm since T + 6mm is removed?
Consider for Eg a "Curve A material" B31.3 with reference MDMT 0C
The PQR thickness is 14.3mm whose MDT is 2.8C(table 323.2.2A B31.3) and hence impact tested @ 0C.
How can this qualify for 28.6mm whose MDT as per the above table is 23.6C? for MDMT 0C?
How can 2T qualification be logical?
Shouldn't T+0(or 14.3mm) is the maximum qualified???
Thanks in advance for your inputs
Edit 1:-
In addition to above does not the thicker material is more prone to brittle fracture?. So if ASME sec. 9 restricts the minimum qualified, is it not relevant that the thicker material tests be more stringent?