Eng-Tareq
Structural
- Jun 19, 2023
- 23
Hello All,
I have a question that I was wondering about for a while. Many steel column base plates are designed to sit on a pedestal that connects to any foundation type below. These pedestals are usually tight and slightly bigger than the base plate (maybe 2" in every direction). I was always wondering how these anchor bolts pass the code checks when it comes to "Concrete breakout resistance of Anchor in Tension" when the full length of embedment probably will not be realized as it can't develop in the concrete. Referring to Canadian codes (CSA A23.3-14 - D6.2) here:
hef=max(Ca,max/1.5; s/3)
Where:
hef: Depth of Embdement used in calculations
Ca,max: Maximum Distance from the Anchors to one of the closest edges
s: Maximum spacing between anchors
This hef value feeds directly into Nbr: Basic concrete breakout strength of a single anchor in tension
Where:
Nbr=kc*Φc*λa*√f'c*hef1.5*R
So if you have a base plate slightly bigger than the column and a pedestal slightly bigger than the base plate hef becomes small, therefore how do these pass code requirements?
See a picture of a real-life example:
I have a question that I was wondering about for a while. Many steel column base plates are designed to sit on a pedestal that connects to any foundation type below. These pedestals are usually tight and slightly bigger than the base plate (maybe 2" in every direction). I was always wondering how these anchor bolts pass the code checks when it comes to "Concrete breakout resistance of Anchor in Tension" when the full length of embedment probably will not be realized as it can't develop in the concrete. Referring to Canadian codes (CSA A23.3-14 - D6.2) here:
hef=max(Ca,max/1.5; s/3)
Where:
hef: Depth of Embdement used in calculations
Ca,max: Maximum Distance from the Anchors to one of the closest edges
s: Maximum spacing between anchors
This hef value feeds directly into Nbr: Basic concrete breakout strength of a single anchor in tension
Where:
Nbr=kc*Φc*λa*√f'c*hef1.5*R
So if you have a base plate slightly bigger than the column and a pedestal slightly bigger than the base plate hef becomes small, therefore how do these pass code requirements?
See a picture of a real-life example: