dpsmith85
Mechanical
- Apr 8, 2011
- 10
I am looking into buying a brake motor to support a vertical load. Our current design is a 200 to 1 two stage reduction gear reducer. The torque at the output of the reducer is around 3500in-lbs. I am looking at a leeson brake motor catalog #114167 that's brake can support 72in-lbs of torque. Based on that the calculation be as simple as:
1) 3500in-lbs/.7 = 5000in-lbs <-------I'm increasing the output torque to account for the loss of efficiency of the gearbox
2) 5000in-lbs/200 = 25in-lbs <-------I'm now dividing the torque at the output by the gear ratio to get the input torque at the shaft
Because 25in-lbs is less than the rated 72in-lbs I should be good correct?
I just want to make sure I'm thinking about this correctly
Thanks
1) 3500in-lbs/.7 = 5000in-lbs <-------I'm increasing the output torque to account for the loss of efficiency of the gearbox
2) 5000in-lbs/200 = 25in-lbs <-------I'm now dividing the torque at the output by the gear ratio to get the input torque at the shaft
Because 25in-lbs is less than the rated 72in-lbs I should be good correct?
I just want to make sure I'm thinking about this correctly
Thanks