BS EN 1991-1-4 Wind Actions

[id_rom]

Good afternoon. In formulas 4.8 and 4.10 I can not figure out how the measurement system. q?

 

[Guest262653]

rho in kg/m3
vb in m/s
qb in Pa

That leads to:
- force [kg.m.s-2] = [N]
- pressure [kg.m.s-2.m-2] = [kg.m-1.s-2] = [Pa]
- qb [kg.m-3.m2.s-2] = [kg.m-1.s-2] = [Pa]

 

[id_rom]

Many thanks!

 

[id_rom]

Is there a project or an example where the Wind Actions is applied?

 

[ilyas415]

For your most recent question:

It somewhat depends what you're trying to apply it for.
If its a building, you might want to generate floor-by-floor diaphragm loads.
If it's a roof/canopy, then you might want to consider area pressures.

The usefulness of any example then depends on what type of structure you're analysing.

-------------
Ilyas

 

[Guest262653]

There's a lot of publications in the European Commission JRC's website:
Link

 

[id_rom]

Thanks for the help. What is the difference between wind pressure (5.2) and wind forces (5.3), and what kind of load should be applied to the building facade?

 

[klaus.]

What is the difference between wind pressure (5.2) and wind forces (5.3)

well.... pressure is force divides by area ....
Wind force is given in [KN]
Wind pressure is given in [KN/m^2]

Are you student ???