dgallup
Automotive
- May 9, 2003
- 4,708
I have an insert molded piece of plastic that has a bilateral surface profile tolerance of 0.020 (.010 in either direction). We have traced across the surface using a profilometer in 2 orthogonal directions and recorded the highest positive and negative deviations from nominal. Various people have proposed 3 different ways to calculate the process capability from this data:
1) Calculate individual capability for the deviation in each direction using half the total tolerance (.010), take the smallest result.
2) Calculate the capability using the absolute value of the largest deviation (positive or negative) and half the total tolerance (.010).
3) Calculate the capability using the largest signed deviation and the total tolerance (.020).
Needless to say, these methods give 3 different results. Any ideas what would be the correct way? I'm open to other methods.
I really don't see this as giving a true statistical representation of the surface as the vast majority of the data is thrown out and only the extremes are being used.
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The Help for this program was created in Windows Help format, which depends on a feature that isn't included in this version of Windows.
1) Calculate individual capability for the deviation in each direction using half the total tolerance (.010), take the smallest result.
2) Calculate the capability using the absolute value of the largest deviation (positive or negative) and half the total tolerance (.010).
3) Calculate the capability using the largest signed deviation and the total tolerance (.020).
Needless to say, these methods give 3 different results. Any ideas what would be the correct way? I'm open to other methods.
I really don't see this as giving a true statistical representation of the surface as the vast majority of the data is thrown out and only the extremes are being used.
----------------------------------------
The Help for this program was created in Windows Help format, which depends on a feature that isn't included in this version of Windows.