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Dimension Problem

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bryjarmoc

Aerospace
Sep 20, 2005
28
I am not sure if this is the correct forum to ask this. See attached picture. I am trying to find out the dimension of "X". If anyone knows the formula for this please let me know.

Thanks
 
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Pythagorus and some subtraction will get it for you.

You have the lengths of 2 sides of the triangle. Use pythagorus theorum to find the length of the remaining side. Subtract this from the radius and voila, unless I'm missing something or showing how dumb I really am.

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I subtractified before I Pathagorized.

Simple inspection and a bit of reflection should get you to the obvious "duh" answer too.
 
bryjarmoc,

As other Guys suggested a combination of Pythagorean theorem and elementary substraction will get you there. The formula is:
(3.310-x)^2+(0.860)^2=(3.310)^2
You will obtain two solutions, which are both theoretically correct. However the smaller one is the one you are looking for.
 
...two solutions, which are both theoretically correct

Did quantum mechanics slip in here somehow? ;-)

"Good to know you got shoes to wear when you find the floor." - [small]Robert Hunter[/small]
 
CheckerHater,
Believe me or not, the solution you gave leads to the same result as mine :)
your C = my x
your B = my (3.310-x)
It's hard to obtain different results in the problem like this.
However I agree that your method is much more clear.
 
ewh, well, there are always 2 solutions to a square root question.

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Thanx, KENAT.

"Good to know you got shoes to wear when you find the floor." - [small]Robert Hunter[/small]
 
Well, enough middle school math revision for me, when do the high school questions start;-).

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pmarc,

There is no X (or C) in your equation.

That's what still confuses me.

 
"the obvious "duh" answer too." What, draw it out in CAD?;-)

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