Dissipating load 3

[DownHillHero]

I am trying to figure out how to mount a bar that will dissipate the forces from a torque.

The bar will be slipped into a hollow square beam that is located 6" from the point where the torque is applied and it extends 8". There will be 3 bolts placed along the hollow square beam at 2", 4" and 6"

The calculation to find the forces at bolts A, B and C would be T = A*8 + B*10 + C*12
Since I only have one equation and three unknowns how can I calculate the force at each bolt?

Attached is an image of the situation.

 

[DownHillHero]

Thanks dhengr, I think I understand what your getting at now, but just to make sure lets see I can describe it back to you.

To start the outer tube will be .5" higher therefore giving us the .25" in clearance between the bar and tube. There will be two .25"x.25" bar inserted in between the bar and tube at the location you specified. The middle bolt will remain to hold the bar in the tube. One question I have is that would we assume that the bolt has no reaction forces?

I also noticed from your earlier post that you have asked if there are any other load involved with the bar. This is where the situation become tricky because yes there are other forces on the bar and it would be very wrong to not include them.

Here's more description of the situation. The piece being analyzed will be mounted into a longer structure to hold it up. The torque on the left end of the bar comes from a torsion bar that has already been twisted. (I am unsure if it is correct to treat that as a moment at the end of the bar.) I have included a picture to help show what I am describing.

I still think the advice you gave will be useful for the situation.

 

[chicopee]

See my attachment for an accepted method using the proportionality constant method for statically indeterminate systems. Note the assumptions.