jheidt2543
Civil/Environmental
- Sep 23, 2001
- 1,469
I found the following statement in one of the responses to a forum question. I would like to hear some opinions/discussion regarding FS relating to this following statement:
“I would calculate the bending moment based on the real load, not the safety factor. AISC has its own safety factor built in the allowable stresses. If you use a SF of 2 in your loads, and compound those SF built in AISC allowable, then you are over sizing the beam!”
For a steel beam, using A36 steel and the allowable stress in bending is 24 ksi (yes, depending on compact section provisions it could be 22 ksi), the reduction is (1-24/36) or 33%. I have always viewed this reduction as the result of some “uncertainty” in the average allowable stress of A36 steel, call it a factor of safety for material properties.
The IBC 2000 code requires that dead loads be increased by 40% and live loads by 70%, factors of safety due to the “uncertainty” of the loading conditions. Now if we combined these two (assuming for this example that DL=LL) then we have introduced a FS of 33% + [(40%+70%)/2] = 88%.
For the same beam in concrete, with a phi of .85, the material factor of safety would be 15% and the code required factored loads would still be 55% for a total of 70%. I would think that there is less variation in the material properties of steel than concrete, but this little analysis doesn’t show it.
Does this seem right??? Is the above thread response correct? It seems to me that the writer's comment leaves out the code required load factors. (Names and dates are left out to protect the innocent <g>)
“I would calculate the bending moment based on the real load, not the safety factor. AISC has its own safety factor built in the allowable stresses. If you use a SF of 2 in your loads, and compound those SF built in AISC allowable, then you are over sizing the beam!”
For a steel beam, using A36 steel and the allowable stress in bending is 24 ksi (yes, depending on compact section provisions it could be 22 ksi), the reduction is (1-24/36) or 33%. I have always viewed this reduction as the result of some “uncertainty” in the average allowable stress of A36 steel, call it a factor of safety for material properties.
The IBC 2000 code requires that dead loads be increased by 40% and live loads by 70%, factors of safety due to the “uncertainty” of the loading conditions. Now if we combined these two (assuming for this example that DL=LL) then we have introduced a FS of 33% + [(40%+70%)/2] = 88%.
For the same beam in concrete, with a phi of .85, the material factor of safety would be 15% and the code required factored loads would still be 55% for a total of 70%. I would think that there is less variation in the material properties of steel than concrete, but this little analysis doesn’t show it.
Does this seem right??? Is the above thread response correct? It seems to me that the writer's comment leaves out the code required load factors. (Names and dates are left out to protect the innocent <g>)