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find temp knowing the humidity ratio and enthalpy

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henegg

Mechanical
Joined
Nov 2, 2007
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15
Location
US
hi

Problem: Have a dryer that is evaporating water off a product at a rate of 2923 lbs of water/hr. If we pull room air at 70F @ 50%RH at rate of 23738 lbs/hr.
What is the temperature of the resulting air stream?what formulas do I use?
 
If that's all you know about the process then you can't get there.
 
dry bulb temp of 70 with a 50% RH means your wet bulb temp is about 58.5 and enthalpy is 25.33 btu/lb

if youre at 1000 cfm the temprature of the 2nd airstream would be 81 degrees F.

If this information was not at all useful to you or anybody else I apologize.
 
Without any kind of calculation - like 500degF or something?!

You are adding roughly 0.1 lb/lb, when your room air normally contains around 0.01 lb/lb. If you have any hope of removing this much water with this much air, it will need to be jet wash from an F-18.

 
thanks for the feed back.

we are planing having a air stream of 5000cfm.

MattyWaste how did you calculate or find 81 F?


thanks again
Tom
 
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