michaelb7
Mechanical
- May 6, 2015
- 16
I have a decoking valve that is mounted with anchor bolts. The valve is experiencing forces and torques in many directions. I need to find the tensile stress and shear stress in each anchor bolt. To me it makes sense to break up the problem into finding the tensile stress, then finding the shear stress. For now, I’d like to focus on finding the tensile stress in each bolt. Based on the shape/bulkiness of my decoking valve, I’m assuming that it is rigid compared to the bolts.
I’m not looking for a numerical answer yet, I just need help with my method. I’d like to solve a simplified version of this just to make sure I’m thinking about it correctly. Here is a simplified version:
A rigid unit cube is supported by 4 bolts at each corner. An arbitrary vertical force is applied somewhere on the cube. The bolts all have the same spring constant k. Find the reaction at each bolt.
Net forces in each direction:
ΣFx = 0; ΣFy = 0; ΣFz = 0
Net moment about arbitrary point P on x-y plane
ΣMPx= 0; ΣMPy = 0; ΣMPz = 0
I choose to do moments about an arbitrary point P rather than about the origin axes. I did this so that the forces from the reactions are not eliminated from the moment equations. (Note: I didn’t bother to expand out ΣFz = 0; ΣMPx= 0; ΣMPy = 0; into the forces, reactions and distances. I figured it could easily enough be done, but it wasn’t the part I needed help with.)
There are no forces in x or y directions and no moment about the Pz axis. We now have 3 equations.
ΣFz = 0; ΣMPx= 0; ΣMPy = 0;
And 4 unknowns (the vertical reactions at each bolt):
A, B, C, D.
I draw a free body diagram of each bolt. Since each bolts has the same spring constant:
A = kδA; B = kδB; C = kδc; D = kδD;
Now I have 7 equations:
ΣFz = 0; ΣMPx= 0; ΣMPy = 0; A = kδA; B = kδB; C = kδc; D = kδD;
And 8 unknowns:
A, B, C, D, δA, δB, δC, δD
(the spring constant of the bolts, the arbitrary force location and magnitude, and the location of P are all knowns)
Now I’ve reached the step where I’m having difficulty with this problem. I have 7 equations and 8 unknowns. I need more equations. Since the cube is a rigid body, the bolts must all lie on the same plane after they deform (there is some plane that could rest on the top of each bolt). I know the generalized equation of a plane is:
ax + by + cz + d = 0
I re-arrange the equation so that the plane is expressed as a function of z:
z = -(a/c)x-(b/c)y-d/c
My questions are:
1) It seems to me the deformation of each bolt (δA, δB, δC, δD) can be expressed as z from the equation: z = -(a/c)x-(b/c)y-d/c
Is this correct? It gives me 4 more equations:
δA = -(a/c)x-(b/c)y-d/c
δB = -(a/c)x-(b/c)y-d/c
δC = -(a/c)x-(b/c)y-d/c
δD = -(a/c)x-(b/c)y-d/c
How to I put these 4 equations into a more useful form?
2) I believe that -a/c is the slope of the plane in the x direction and -b/c is the slope in the y direction and -d/c is the offset from the z axis. I think I should either:
a) combine -a/c, -b/c and –d/c into their own variables (-a/c = L, -b/c = M, -d/c = N) so that each bolt is deforming δ = Lx + My + N
b) express –a/c, -b/c and -d/c as some trigonometric relationship based on the geometry I have.
c) do something different, what do you guys recommend?
After I get these final four equations nailed down I’m thinking I’ll have 11 equations and 11 unknowns, then I can solve them with a linear algebra solver. Once I’m convinced I’m doing the simple case correctly, I can move on to my actual calculation. Any suggestions or comments are greatly appreciated!
I’m not looking for a numerical answer yet, I just need help with my method. I’d like to solve a simplified version of this just to make sure I’m thinking about it correctly. Here is a simplified version:
A rigid unit cube is supported by 4 bolts at each corner. An arbitrary vertical force is applied somewhere on the cube. The bolts all have the same spring constant k. Find the reaction at each bolt.
Net forces in each direction:
ΣFx = 0; ΣFy = 0; ΣFz = 0
Net moment about arbitrary point P on x-y plane
ΣMPx= 0; ΣMPy = 0; ΣMPz = 0
I choose to do moments about an arbitrary point P rather than about the origin axes. I did this so that the forces from the reactions are not eliminated from the moment equations. (Note: I didn’t bother to expand out ΣFz = 0; ΣMPx= 0; ΣMPy = 0; into the forces, reactions and distances. I figured it could easily enough be done, but it wasn’t the part I needed help with.)
There are no forces in x or y directions and no moment about the Pz axis. We now have 3 equations.
ΣFz = 0; ΣMPx= 0; ΣMPy = 0;
And 4 unknowns (the vertical reactions at each bolt):
A, B, C, D.
I draw a free body diagram of each bolt. Since each bolts has the same spring constant:
A = kδA; B = kδB; C = kδc; D = kδD;
Now I have 7 equations:
ΣFz = 0; ΣMPx= 0; ΣMPy = 0; A = kδA; B = kδB; C = kδc; D = kδD;
And 8 unknowns:
A, B, C, D, δA, δB, δC, δD
(the spring constant of the bolts, the arbitrary force location and magnitude, and the location of P are all knowns)
Now I’ve reached the step where I’m having difficulty with this problem. I have 7 equations and 8 unknowns. I need more equations. Since the cube is a rigid body, the bolts must all lie on the same plane after they deform (there is some plane that could rest on the top of each bolt). I know the generalized equation of a plane is:
ax + by + cz + d = 0
I re-arrange the equation so that the plane is expressed as a function of z:
z = -(a/c)x-(b/c)y-d/c
My questions are:
1) It seems to me the deformation of each bolt (δA, δB, δC, δD) can be expressed as z from the equation: z = -(a/c)x-(b/c)y-d/c
Is this correct? It gives me 4 more equations:
δA = -(a/c)x-(b/c)y-d/c
δB = -(a/c)x-(b/c)y-d/c
δC = -(a/c)x-(b/c)y-d/c
δD = -(a/c)x-(b/c)y-d/c
How to I put these 4 equations into a more useful form?
2) I believe that -a/c is the slope of the plane in the x direction and -b/c is the slope in the y direction and -d/c is the offset from the z axis. I think I should either:
a) combine -a/c, -b/c and –d/c into their own variables (-a/c = L, -b/c = M, -d/c = N) so that each bolt is deforming δ = Lx + My + N
b) express –a/c, -b/c and -d/c as some trigonometric relationship based on the geometry I have.
c) do something different, what do you guys recommend?
After I get these final four equations nailed down I’m thinking I’ll have 11 equations and 11 unknowns, then I can solve them with a linear algebra solver. Once I’m convinced I’m doing the simple case correctly, I can move on to my actual calculation. Any suggestions or comments are greatly appreciated!