Force decomposition in a clutch

[stev0]

Hi All,
My first post. I am an electronics person straying into mechanical engineering. I am teaching myself FEA on Simscale.

This is a heavy 1960s cast iron car clutch used (strangely) in a motorcycle. It needs slimming down. Part 19 is the input. Part 15 is the output. I want to FEA part 12. I fix the front face of part 12. I must then apply the rated torque and load 12. As i see it this torgue transmission is divided between both faces of the clutch plate, part 15. So, the torque is divided between the friction face of 12 and the friction face of part 16. Part 16 loads 12 via its three fingers. Is this the case? I find rotational stuff can defeat my intuition.

Part 18 is the spring. The clutch is released by a pull rod pulling inside 16.

Ultimately I will add the spring force, centrifugal force and torque.

 

[desertfox]

Hi

Have you a specific question?

“Do not worry about your problems with mathematics, I assure you mine are far greater.” Albert Einstein

 

[stev0]

Is the torque divided equally between the friction faces of 12 and 16. My inclination is yes as if it were different some parts would be in motion w.r.t. 12 or 16. With the clutch fully engaged this is not the case.

 

[desertfox]

Hi

I would say the torques are equal on both faces but not shared.

https://mechanics.stackexchange.com/questions/18552/how-does-a-clutch-work

“Do not worry about your problems with mathematics, I assure you mine are far greater.” Albert Einstein