ServoWizard
Electrical
- May 21, 2005
- 17
Hello,
I'm trying to calculate the GPH of fuel required to maintain a 6.5:1 Air to Fuel ratio. My engine displaces 400 cubic inches, but being a 4 cycle it actually pumps 200 cubic inches per revolution. The engine will operate at a maximum RPM of 8000.
200 * 8000 = 1,600,000 cubic inches pumped per minute.
1 Gallon = 231 cubic inches.
So here I multiply the single unit by the AFR
231 * 6.5 = 1501.5 (6.5 Units)
1501.5 + 231 = 1732.5 (Total Mixure or 6.5 parts Air + 1 part Fuel)
231 / 1732.5 = .1333 (231 represents 13.3% of Total Mixure)
Now using the same logic with the exception that I reduce the total cubic inches down to 1 unit.
1,600,000 / 6.5 = 246153.8462 (1 Unit = 246153.8462)
6.5 Units + 1 Unit = 1846153.8462 (Total Mixure or 6.5 parts Air + 1 part Fuel)
246153.8462 / 1846153.8462 = .1333 (246153.8462 represents 13.3% of Total Mixure))
246153.8462 / 231 = 1065.601 Gallons Per Minute = WRONG!
I'm obviously in over my head. I would appreciate some help.
Thanks,
Ron
I'm trying to calculate the GPH of fuel required to maintain a 6.5:1 Air to Fuel ratio. My engine displaces 400 cubic inches, but being a 4 cycle it actually pumps 200 cubic inches per revolution. The engine will operate at a maximum RPM of 8000.
200 * 8000 = 1,600,000 cubic inches pumped per minute.
1 Gallon = 231 cubic inches.
So here I multiply the single unit by the AFR
231 * 6.5 = 1501.5 (6.5 Units)
1501.5 + 231 = 1732.5 (Total Mixure or 6.5 parts Air + 1 part Fuel)
231 / 1732.5 = .1333 (231 represents 13.3% of Total Mixure)
Now using the same logic with the exception that I reduce the total cubic inches down to 1 unit.
1,600,000 / 6.5 = 246153.8462 (1 Unit = 246153.8462)
6.5 Units + 1 Unit = 1846153.8462 (Total Mixure or 6.5 parts Air + 1 part Fuel)
246153.8462 / 1846153.8462 = .1333 (246153.8462 represents 13.3% of Total Mixure))
246153.8462 / 231 = 1065.601 Gallons Per Minute = WRONG!
I'm obviously in over my head. I would appreciate some help.
Thanks,
Ron