Your made a mistake in your math 50*(10.74+0.8)/5.2 = 110.96
This assumes that the moment is taken up by shear in both the left and right side bolts evenly. I don't think in reality this what will happen. The bolt holes for a shear connection I believe are about 1/16" larger than the bolt diameter. I think what will really happen is that as the inner box wants to rotate about the bolt holes, before contact is made between the bolts and the connecting plate of the boxes (causing the shear force), There will be prying action that will put the left side bolt in tension (prying force) with an associated proped beam reaction force of the outer box on the inner box at the top left acting to the right. On the right side the bottom horizontal plate will be much stiffer than the vertical right side plate so the force of resistance on that side will a be force on the outer box acting on the inner box at the bottom without any prying action on the right side bolt. This assumes plates are rigid and don't bend under bending stress. However the plates are actually flexible (1/16" thick) so loads of outer box on inner box are not point loads but spread out along the vertical plane in a triagular pressure pattern, which I think comes down to a very complicated equation and may be indeterminant.