Andres9292
Mechanical
- Jun 30, 2020
- 12
Hi everyone, Im trying to select an appropriate dc brushless motor to design a Power Soccer wheelchair. I already did my calculations, but I did it 2 ways and my answers are not the same. Please help. Here is the design problem:
I have the "cart" weighs 150 kg and has to be able to have 150 kg capacity, so it is a 300 kg body. It has to have 2 motors: each attatched to a gearbox and then to a 10" diameter wheel.
For now, the variables I chose for my design are:
The cart has to reach 14.36 km/h or 3.99 m/s and must reach its max speed after 1.6 seconds. The motor has a rated speed of 2400 and a gearbox of 1:8 ratio.
I tried finding the power and torque 2 different ways, but they dont match. The first calculation I did was:
Cart max speed
vcart= Pi*(D)*nwheel = 3.14*0.254(m)*300(rpm)/60(sec/min)= 3.99 m/s = 14.36 km/h
Transition speed
vcart= (3.99/1.6)t
vcart= 2.49 t
Acceleration
a=2.49 m/s^2
Force needed to reach 3.99 m/s in 1.6 sec
F=ma=300*2.49= 780.51 N
1st method
Up until this point there isnt any problem. But now i use 2 different methods to find power and torque. The first one I did using the procedure found in this website:
Distance traveled
d=d0+v0*t+a*(t^2)/2= 2.49*(1.6^2)/2= 3.19m
Power required
P=F*d/t= 780.51*3.19/1.6= 1557 W
Since there are 2 motors, each motor needs to be
Pm= P/2= 778 W = 1 HP
Wheel Torque
Tw=9.55*P/nwheel= 9.55*778/300= 24.78 Nm
Motor Torque
Tm= 9.55*P/nmotor= 9.55*778/2400= 3.1 Nm
2nd method
Force required by each wheel
Fw=F/2= 390.25N
Torque required for each wheel
Tw=F*r= 390.25(N)*0.127(m)= 49.56 Nm
Torque required for each motor
Tm= 49.56/8= 6.29 Nm
Power required for each motor
Pm= T*n/9.55= 6.29*2400/9.55= 1557 W = 2 HP
As you can see, 1 calculation says the motor needs 1 HP and 3.1 Nm of torque, but the other one says I need double the power and torque. I tried making sure that im not screwing up while considering that there are 2 motors but that doesnt appear to be the problem. Can you help me figure out what is the correct calculation? Is one of these methods flawed?
Thanks
I have the "cart" weighs 150 kg and has to be able to have 150 kg capacity, so it is a 300 kg body. It has to have 2 motors: each attatched to a gearbox and then to a 10" diameter wheel.
For now, the variables I chose for my design are:
The cart has to reach 14.36 km/h or 3.99 m/s and must reach its max speed after 1.6 seconds. The motor has a rated speed of 2400 and a gearbox of 1:8 ratio.
I tried finding the power and torque 2 different ways, but they dont match. The first calculation I did was:
Cart max speed
vcart= Pi*(D)*nwheel = 3.14*0.254(m)*300(rpm)/60(sec/min)= 3.99 m/s = 14.36 km/h
Transition speed
vcart= (3.99/1.6)t
vcart= 2.49 t
Acceleration
a=2.49 m/s^2
Force needed to reach 3.99 m/s in 1.6 sec
F=ma=300*2.49= 780.51 N
1st method
Up until this point there isnt any problem. But now i use 2 different methods to find power and torque. The first one I did using the procedure found in this website:
Distance traveled
d=d0+v0*t+a*(t^2)/2= 2.49*(1.6^2)/2= 3.19m
Power required
P=F*d/t= 780.51*3.19/1.6= 1557 W
Since there are 2 motors, each motor needs to be
Pm= P/2= 778 W = 1 HP
Wheel Torque
Tw=9.55*P/nwheel= 9.55*778/300= 24.78 Nm
Motor Torque
Tm= 9.55*P/nmotor= 9.55*778/2400= 3.1 Nm
2nd method
Force required by each wheel
Fw=F/2= 390.25N
Torque required for each wheel
Tw=F*r= 390.25(N)*0.127(m)= 49.56 Nm
Torque required for each motor
Tm= 49.56/8= 6.29 Nm
Power required for each motor
Pm= T*n/9.55= 6.29*2400/9.55= 1557 W = 2 HP
As you can see, 1 calculation says the motor needs 1 HP and 3.1 Nm of torque, but the other one says I need double the power and torque. I tried making sure that im not screwing up while considering that there are 2 motors but that doesnt appear to be the problem. Can you help me figure out what is the correct calculation? Is one of these methods flawed?
Thanks