jmme
Civil/Environmental
- Mar 9, 2011
- 25
See attached picture of the plans.
The guy who drew the plans shows a 2x8 (12' long) on each side of the 6x6 post. The trusses will sit on these two 2x8. The snow load in my area is 55 psf. Based on this the load on the beam will be 55 psf x 19.5 ft (bldg is 39 feet wide so 19.5 is half) = 1072.5 lb/ft. If I use the M=wl^2/8 I get 1072.5 x(12ft)^2 / 8 = 19,305 ft.lb = 231,660 in.lb. This load is way to much for two 2x8 to carry.
Even if you change the length from 12' to 8' you still get 102,960 in.lb. I just saw a similar building and they used the same construction with the 6x6 posts 8' apart and two 2x12 so I know this type of construction works.
Am I doing my calculations wrong or what am I missing?
Thanks.
The guy who drew the plans shows a 2x8 (12' long) on each side of the 6x6 post. The trusses will sit on these two 2x8. The snow load in my area is 55 psf. Based on this the load on the beam will be 55 psf x 19.5 ft (bldg is 39 feet wide so 19.5 is half) = 1072.5 lb/ft. If I use the M=wl^2/8 I get 1072.5 x(12ft)^2 / 8 = 19,305 ft.lb = 231,660 in.lb. This load is way to much for two 2x8 to carry.
Even if you change the length from 12' to 8' you still get 102,960 in.lb. I just saw a similar building and they used the same construction with the 6x6 posts 8' apart and two 2x12 so I know this type of construction works.
Am I doing my calculations wrong or what am I missing?
Thanks.