xj25
Electrical
- May 7, 2011
- 110
I found this topic in thread798-186885.
There are two references for online calculator/graphic data
Usig both I get:
online:
Flow medium: air / gaseous
Volume flow: 690 m³/h
Weight density: 1.2 kg/m³
Dynamic Viscosity: 15.11 10-6 kg/ms
Element of pipe: Perforated plate thin circular
Dimensions of element: Diameter of pipe D: 297 mm (equivalent area of 0,07m2)
Clear area in %: 47
Velocity of flow: 2.77 m/s
Reynolds number: 65255 Flow: turbulent
Resistance coefficient: 5.35
Pressure drop: 0.25 mbar (25Pa)
from given graph in pdf:
v_mean = 690m3/h / 0.033m2 (perforated area) = 5.8m/s = 1100fpm
47% open area
So about 0.25inches of water = 62Pa
another online option:
v_mean = 690m3/h / 0.033m2 = 5.8m/s
47% open area
gives about 60-70Pa (graph solution)
First online solver seems quite lower (25Pa against 60), it seems because it considers a velocity (2.8m/s) quite lower than simple mean velocity (5.8m/s)
¿any idea why?
Thanks for reading!
There are two references for online calculator/graphic data
Usig both I get:
online:
Flow medium: air / gaseous
Volume flow: 690 m³/h
Weight density: 1.2 kg/m³
Dynamic Viscosity: 15.11 10-6 kg/ms
Element of pipe: Perforated plate thin circular
Dimensions of element: Diameter of pipe D: 297 mm (equivalent area of 0,07m2)
Clear area in %: 47
Velocity of flow: 2.77 m/s
Reynolds number: 65255 Flow: turbulent
Resistance coefficient: 5.35
Pressure drop: 0.25 mbar (25Pa)
from given graph in pdf:
v_mean = 690m3/h / 0.033m2 (perforated area) = 5.8m/s = 1100fpm
47% open area
So about 0.25inches of water = 62Pa
another online option:
v_mean = 690m3/h / 0.033m2 = 5.8m/s
47% open area
gives about 60-70Pa (graph solution)
First online solver seems quite lower (25Pa against 60), it seems because it considers a velocity (2.8m/s) quite lower than simple mean velocity (5.8m/s)
¿any idea why?
Thanks for reading!