postTensionBeginner
Mechanical
- Feb 20, 2010
- 6
I am trying to understand the basic physics of post-tensioning. Consider the following:
Concrete hollow cylinder, say 5cm in diameter has a hole of diameter 1cm. Put a steel bolt of dia 0.75cm, put a nut at the bottom and top; post-tension it to 10Newtons. I stick this in the ground. Assume the bolt sticks out of the ground, all the concrete cylinder is in the ground.
Force balance:
a) Concrete will have 5N of force on the top from the top nut, 5N of force from the bottom nut.
b) The bolt is being pulled 5N from top and 5N from bottom. All forces match.
Now I apply a vertical force of 2N to the bolt that is sticking out of the ground.
Force balance on the cylinder:
a) on the vertical surface of the cylinder, the soil will exert a downward force of 2N (negative)
b) on the bottom surface the nut will still exert 5N (positive)
c) on the top surface the nut will exert 3N of force (negative). this force gets reduced due to the 2N force that was applied
Force balance on the bolt:
a) on the bottom the cylinder pushes by 5N (negative)
b) on the top the cylinder pushes by 3N (positive)
c) the external force is 2N (positive)
So the force on the bolt does not change, it stays tensioned at 10N (I am not sure if it is called 5N of tension or 10N of tension).
Please let me know if this is correct.
thanks
Concrete hollow cylinder, say 5cm in diameter has a hole of diameter 1cm. Put a steel bolt of dia 0.75cm, put a nut at the bottom and top; post-tension it to 10Newtons. I stick this in the ground. Assume the bolt sticks out of the ground, all the concrete cylinder is in the ground.
Force balance:
a) Concrete will have 5N of force on the top from the top nut, 5N of force from the bottom nut.
b) The bolt is being pulled 5N from top and 5N from bottom. All forces match.
Now I apply a vertical force of 2N to the bolt that is sticking out of the ground.
Force balance on the cylinder:
a) on the vertical surface of the cylinder, the soil will exert a downward force of 2N (negative)
b) on the bottom surface the nut will still exert 5N (positive)
c) on the top surface the nut will exert 3N of force (negative). this force gets reduced due to the 2N force that was applied
Force balance on the bolt:
a) on the bottom the cylinder pushes by 5N (negative)
b) on the top the cylinder pushes by 3N (positive)
c) the external force is 2N (positive)
So the force on the bolt does not change, it stays tensioned at 10N (I am not sure if it is called 5N of tension or 10N of tension).
Please let me know if this is correct.
thanks