Loo Kian Sing
Mechanical
- Apr 12, 2017
- 38
Let's say a centrifugal pump is designed to operate at a flow rate of 10 m3/hr with head of 50 m.
If the liquid from the suction is not enough to be pumped (only 5 m3/hr liquid is available):
1) Will the pump still function at the designed rpm?
2) Will the pump capacity still remain as 10 m3/hr or change to 5 m3/hr?
3) Will the NPSHr of the pump changes (that might caused by the capacity of pump)?
4) Will the suction pressure and NPSHa decrease?
5) Will the cavitation happen (due to the insufficient liquid to be pumped) although NPSHa (after decreases of NPSHa that might caused by insufficient liquid available) is still higher than NPSHr?
Thank you for anyone who pay attention to the question i ask.
If the liquid from the suction is not enough to be pumped (only 5 m3/hr liquid is available):
1) Will the pump still function at the designed rpm?
2) Will the pump capacity still remain as 10 m3/hr or change to 5 m3/hr?
3) Will the NPSHr of the pump changes (that might caused by the capacity of pump)?
4) Will the suction pressure and NPSHa decrease?
5) Will the cavitation happen (due to the insufficient liquid to be pumped) although NPSHa (after decreases of NPSHa that might caused by insufficient liquid available) is still higher than NPSHr?
Thank you for anyone who pay attention to the question i ask.