RFreund
Structural
- Aug 14, 2010
- 1,881
I am checking a soldier pile design with 'mixed soils' (i.e. uses friction angle and cohesion). The way I typically apply lateral earth pressures to the pile is to multiple the active forces above the dredge line by the pile spacing and the passive & active forces below the dredge line by the effective width of the pile. This is essentially multiplying the unit weight of the soil by the pile spacing and/or effective width. My question is the same done for the cohesion value? For example, let's say I have a soils with:
Unit weight g=120pcf
Cohesion c=250psf
Friction angle of 26 deg
6' pile spacing
When I'm finding the active pressure on the pile I will multiple the unit weight by 6. When finding passive resistance, I will multiply by something between 2 and 3. Would I also multiply the cohesion by the pile spacing? I want to say yes and this should be obvious, but something has me questioning it. I want to say yes because when you look at your pressure diagram you would subtract 2c from your pressure diagram which is your unit weight x Ka and if your are factoring up your unit weight then you'd need to factor up c as well. I think I've some full circle writing this out...
Thanks!
Unit weight g=120pcf
Cohesion c=250psf
Friction angle of 26 deg
6' pile spacing
When I'm finding the active pressure on the pile I will multiple the unit weight by 6. When finding passive resistance, I will multiply by something between 2 and 3. Would I also multiply the cohesion by the pile spacing? I want to say yes and this should be obvious, but something has me questioning it. I want to say yes because when you look at your pressure diagram you would subtract 2c from your pressure diagram which is your unit weight x Ka and if your are factoring up your unit weight then you'd need to factor up c as well. I think I've some full circle writing this out...
Thanks!