BCpowertrain
Mechanical
- Apr 8, 2009
- 8
Hello,
I am looking for some help in determining the torque required to start a positive displacement reciprocating pump which has its' discharge connected to a manifold under pressure.
The pump in question would either be a triplex or quintuplex piston pump, with known plunger size and plunger stroke, and known manifold pressure that it must start against.
Consider for discussions sake a triplex pump, with a stroke of 5", plunger diameter 3", and a manifold pressure of 10,000 psi which the pump must be started against.
My understanding is that if this were a single cylinder pump, and the pump was to be started at the worst case position where the crank throw was at a right angle to the stroke, then the torque required would be the connecting rod load multiplied by the crank throw [pressure x cylinder area = 10,000 psi x pi()*(1.5^2)] * [1/2 stroke = crank throw].
Can someone please confirm my analogy above for a single piston pump is correct?
Now with a multiple piston pump there must be some formula around that allow for consideration of the effects of the other cylinders, as some would have a rod load from generating pressure at some crank angle other than 90 degrees to the crank throw, and other cylinders would have some rod load requirement the suction work.
If anyone could shed some light on this subject for me it would be much appreciated.
Thanks for your assistance.
I am looking for some help in determining the torque required to start a positive displacement reciprocating pump which has its' discharge connected to a manifold under pressure.
The pump in question would either be a triplex or quintuplex piston pump, with known plunger size and plunger stroke, and known manifold pressure that it must start against.
Consider for discussions sake a triplex pump, with a stroke of 5", plunger diameter 3", and a manifold pressure of 10,000 psi which the pump must be started against.
My understanding is that if this were a single cylinder pump, and the pump was to be started at the worst case position where the crank throw was at a right angle to the stroke, then the torque required would be the connecting rod load multiplied by the crank throw [pressure x cylinder area = 10,000 psi x pi()*(1.5^2)] * [1/2 stroke = crank throw].
Can someone please confirm my analogy above for a single piston pump is correct?
Now with a multiple piston pump there must be some formula around that allow for consideration of the effects of the other cylinders, as some would have a rod load from generating pressure at some crank angle other than 90 degrees to the crank throw, and other cylinders would have some rod load requirement the suction work.
If anyone could shed some light on this subject for me it would be much appreciated.
Thanks for your assistance.