Aug 11, 2006 #1 sdavfc Automotive May 11, 2005 6 GB I am looking for a polymer that will have as near as possible the similar coeffiecient of thermal expansion rate as alluminium. Any suggestions ?
I am looking for a polymer that will have as near as possible the similar coeffiecient of thermal expansion rate as alluminium. Any suggestions ?
Aug 11, 2006 #2 plastx Materials Oct 15, 2003 50 US Go to http://www.matweb.com where you can find cte numbers for polymers and AL. Upvote 0 Downvote
Aug 12, 2006 #3 patprimmer New member Nov 1, 2002 13,816 US Polymers will all be substantially higher. As mentioned Matweb will help as will http://www.rtpcompany.com A material with a lot of reinforcement will get as close as possible. Also beware that polymers can be quite non linear in their thermal expansion. Regards eng-tips, by professional engineers for professional engineers Please see FAQ731-376 for tips on how to make the best use of Eng-Tips Fora. Upvote 0 Downvote
Polymers will all be substantially higher. As mentioned Matweb will help as will http://www.rtpcompany.com A material with a lot of reinforcement will get as close as possible. Also beware that polymers can be quite non linear in their thermal expansion. Regards eng-tips, by professional engineers for professional engineers Please see FAQ731-376 for tips on how to make the best use of Eng-Tips Fora.
Aug 15, 2006 #4 nbucska Electrical Jun 1, 2000 2,191 US It should be posiible to design around. Plesae read FAQ240-1032 My WEB: <http://geocities.com/nbucska/> Upvote 0 Downvote
It should be posiible to design around. Plesae read FAQ240-1032 My WEB: <http://geocities.com/nbucska/>
Aug 16, 2006 Thread starter #5 sdavfc Automotive May 11, 2005 6 GB It looks like my customer will now change the design of the part and glass filled PEEK of which we mould quite a bit already. Thanks to all who replied. Upvote 0 Downvote
It looks like my customer will now change the design of the part and glass filled PEEK of which we mould quite a bit already. Thanks to all who replied.