PalomaP
Mechanical
- May 11, 2007
- 23
When pump working between two tanks, and we apply the bernoulli equation, we normaly consider v1 (suction) and v2 (discharge) = 0 (the area of the tanks very big, so velocities will come very small)
However if the discharge pie is above the liquid level in the discharge tank, i should consider the velocity head?
i.e For suction lift pump, suction tank open atmosphera
discharge tank open atmosphera but discharge pipe above the liquid level.
According to Bernoulli,
Htotal= Hatm1-h1-hf1-v1^2/2g+Hatm2+h2-hf2+v2^2/2g
Hatm1=Hatm2
h1= from liquid level of suction tank to centerline pump
hf1=all friction suction side
v1=0
h2= from centerline discharge pipe to centerline pump
hf2=all friction discharge side
v2=???
Should i take the term v2^2/2g as positive?
so, if i take the velocity head in account as positive value I will add v2^2/2g to the total head. However when calculating friction loss as sudden enlargemente at the end of the discharge line, i will add v2^2/2g but in negative (friction loss).
Could someone confirm it?
Thanks a lot
However if the discharge pie is above the liquid level in the discharge tank, i should consider the velocity head?
i.e For suction lift pump, suction tank open atmosphera
discharge tank open atmosphera but discharge pipe above the liquid level.
According to Bernoulli,
Htotal= Hatm1-h1-hf1-v1^2/2g+Hatm2+h2-hf2+v2^2/2g
Hatm1=Hatm2
h1= from liquid level of suction tank to centerline pump
hf1=all friction suction side
v1=0
h2= from centerline discharge pipe to centerline pump
hf2=all friction discharge side
v2=???
Should i take the term v2^2/2g as positive?
so, if i take the velocity head in account as positive value I will add v2^2/2g to the total head. However when calculating friction loss as sudden enlargemente at the end of the discharge line, i will add v2^2/2g but in negative (friction loss).
Could someone confirm it?
Thanks a lot