Vertical Load distribution on Wheel Rim

[struclearner]

The load on the wheel rim from the weight of the vehicle is assumed having a sinusoidal distribution with an angle of distribution.
The sum of total distributed load will equal to the total force acting on the wheel.
Is the cosine distribution of the load have a vertical component only or it will also have a horizontal component acting on the rim as the load point of application moves away from the center location where the load has only vertical component.
If I need to determine the load to apply for fea, how the sinusoidal distribution of the force can be calculated for an angle increment.
Thank you very much for your help/referring to the link/material dealing with the subject.

 

[hendersdc]

If you are already running a FEA, why don't you just include the hub in the analysis and apply the load to that?

 

[onatirec]

This is the sort of thing you are trying to do?:

https://www.3dcadworld.com/structural-analysis-of-a-wheel-fitted-with-a-pneumatic-tire/

https://forum.ansys.com/discussion/10267/how-to-add-variable-pressure-on-round-surface

 

[Compositepro]

Years ago, when I looked to understand how a pneumatic tire works I came to the conclusion that the vehicle is supported by the bead wires, suspended from the top half of the tire, which is supported by the pneumatic pressure. I am not completely sure this is correct. There may well be different ways of looking at the problem that are useful for different reasons.

 

[hydtools]

Won't the horizontal forces be equal an opposite?

Ted

 

[RRiver]

Just curious but doesn't the NHTSA define the testing standards for manufacturing and testing for wheels\rims?

 

[struclearner]

Dears,
Thanks for your responses and referring to good stuff.
I am clear now about a couple of things, the vertical ground reaction to rim acts sinusoidally and since it is normal to the surface, due to the circular surface, the load will have vertical and horizontal components in a rectangular coordinate system,
Now as hydtools response,
Won't the horizontal forces be equal an(d) opposite?
Yes, the sum of the horizontal forces be zero due to their opposite directions and equal magnitude across the line of symmetry through the zero angle of distribution. But since this is not a rigid body analysis, theses forces are causing deformation and corresponding stresses on the structure.
I am in the process of learning of calculating the forces at the respective locations on the rim, say with 10 degree increment and 120 degree angle of distribution from the total force. I can use FEA software to apply this load as a bearing load, but I would like to learn, how the vertical and horizontal components of the total force with cosine distribution are calculated. The force magnitude at the center location with 0 degree will only have vertical component but the other locations along the circumference do have horizontal components.
I am in the process of figuring this calculations out, I appreciate and thanks a lot for any help and pointing to the right direction.

 

[GregLocock]

To add to Compositepro's post, if you don't understand how the tire loads the wheel then you are just telling stories. I'd consider modelling the whole system, not just the wheel itself.

Cheers

Greg Locock


New here? Try reading these, they might help FAQ731-376

http://eng-tips.com/market.cfm?

 

[JStephen]

The wording sounds an awful lot like homework, actually.