KnacKeN
Mechanical
- Jun 26, 2009
- 13
thread727-148480
Can someone explain the logic of using Von Mises for static failure (i.e. ultimate)? I thought it was only really useful for determining if yielding has occured. Once you get close to failure you're in the non-linear portion of the stress/strain curve, so is Von Mises still relevant?
Isn't Von Mises derived assuming you are more or less witin the limit of proportionality (ie 1/2 stress x strain = area of triangle = area under curve)? The would have thought the equation for distortion strain energy at ultimate failure would look different...?
Can someone explain the logic of using Von Mises for static failure (i.e. ultimate)? I thought it was only really useful for determining if yielding has occured. Once you get close to failure you're in the non-linear portion of the stress/strain curve, so is Von Mises still relevant?
Isn't Von Mises derived assuming you are more or less witin the limit of proportionality (ie 1/2 stress x strain = area of triangle = area under curve)? The would have thought the equation for distortion strain energy at ultimate failure would look different...?