I believe the bent anchor has merit. It's true there is a lateral force at the bend point, but the lower end has much better tensile resistance than either a L or J anchor.
I don't want to participate in a discussion about religion; it's not an appropriate topic on an engineering forum. It has such a strong "hold" on some that they will take extreme measures against one another in the belief they are appeasing their god. That is why I don't like that part.
The first mention of Tekla was by BulbTheBuilder. Prior to that, I was not aware what software you were using (not sure how BtB knew).
Not sure what exactly you are hoping to accomplish in this thread, but it seems to me you will need graphical software capable of labeling various items on...
The occupied area is shown in red below. The beam in question carries only partial live load, so it is understandable that the load to the beam in question would vary. But it's not a major difference and for simplicity, you may wish to use the same size beam on Gridlines B to F inclusive. I...
Vertical reactions Ra and Rd are eliminated using horizontal forces using a strut and tie as shown below. Rb and Rc reduce to 1634#. Minor adjustments in shaft deflection could be made by tightening the tie.
Part of my problem is that you don't label which plan you are showing. The beam in question appears to be on the second level, i.e. the ceiling level. If that is a floor, three edges will not sustain floor load because of roof slope. 2.95 kPa seems high for a ceiling, and if it is a floor...
Thanks Stress Eng,
If the rotation at B and C could be resisted by pure moments applied at each end instead of Ra and Rd acting over a 6" lever arm, the reactions at B, C could be substantially reduced, but that may not be possible with a valve shaft which is required to rotate about its axis...
Well, actually, I had an error in the expression for theta due to Ra and Rd (missing a 2 in the denominator), so you would not have got the correct answer the first time around. We seniors have our good days and bad days.
Eliminating supports A and D, Ra and Rd are each found to be 3215# downward for zero deflection at A, B, C and D. This is in agreement with Doug's result.
Unit load is the load per unit length of beam. In a uniformly loaded beam, unit load w is constant. In the first problem in this thread unit load varied from 0 to a maximum value of w. In the current problem, unit load is 82.815*sin(pi*x/L).
And "deflection = 5.22843E-5" is the computer's...
Here is a printout of the Two Support Beam with span of 74". This explains the problem we are having.
EDIT: Sorry, I misinterpreted the printout. Please ignore this post.
See instead the following two posts by IDS, in which the output is found to be correct.