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Cutting force: formula

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drir

Mechanical
Aug 17, 2011
47
Hi, I want to calculate the tangential cutting force Ft.
Can someone give me a good reference or the formulas?
 
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Hi

You need to be more specific in terms of machining process and the material your cutting
 
Oh sorry! It is for the inside turning of beryllium copper.
 
I do not see any formula in this file in order to calculate my cutting forces.
 
page 7

torque= Fc X D(avg)/2

The torque you get from the power of your lathe depending on rpm of the chuck.

on page 7 Fc = cutting force

this is a copy of page 7:-

TABLE 22.3
N = Rotational speed of the workpiece, rpm
f = Feed, mm/rev or in/rev
v = Feed rate, or linear speed of the tool along workpiece length, mm/min or in/min
=fN
V = Surface speed of workpiece, m/min or ft/min
= π Do N (for maximum speed)
= π Davg N (for average speed)
l = Length of cut, mm or in.
Do = Original diameter of workpiece, mm or in.
Df = Final diameter of workpiece, mm or in.
Davg = Average diameter of workpiece, mm or in.
= (Do +Df ) /2
d = Depth of cut, mm or in.
= ( Do +Df ) /2
t = Cutting time, s or min
=l/f N
MRR = mm3/min or in3/min
= π Davg d fN
Torque = Nm or lb ft
= ( Fc )( Davg /2 )
Power = kW or hp
= (Torque) (w , where w=2π radians/min
 
Desertfox, on page 7 "Three principle forces in turning" shouldn't that be "Three principal forces in turning"?
 
Chicopee

Please re-read and explain your post, I cannot understand your point:-

"Three principle forces in turning" shouldn't that be "Three principal forces in turning"?

The two quotes above are the same.
 
principle
principal

Not the same

TTFN
faq731-376
7ofakss

Need help writing a question or understanding a reply? forum1529
 
Ah thanks IRstuff I see it now.
Yes Chicopee I agree with you, however I won't be writing to the site to correct it.
 
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