zofiron
Aerospace
- Dec 7, 2019
- 2
Hello,
I apologize in advance for my basic understanding of things, I've only been in my trade for a few years. I've learned enough to know what I need to make good manufacturing decisions, but I feel that I'm a bit lacking in knowledge regarding inspection.
Here's the situation: I've got a part that I'm not sure my company is inspecting properly, but nobody here is explaining it to me in a way that makes sense with any of the research and learning regarding GD&T that I've done over the past few years. I'm not able to share the actual data or prints, so I've made a mock drawing (isometric view) that mimics the part surfaces, holes, and tolerances.
See the attached pdf - I'm interested particularly in how the nearest hole (position diameter of .003 to datums A, C, D) would be inspected relative to the datum scheme. My understanding of this positional tolerance is as follows:
A theoretical true position is created at the center point of that hole relating back to the established datums.
A cylindrical tolerance zone with a diameter of .006 is created through the material that the hole is in. (This cylindrical tolerance zone would be normal to the face of that surface, or the theoretical angle of that surface relative to the established datums?)
The axis of the hole (actual condition) must fall within that cylindrical tolerance zone.
The way it is being explained to me, we are analyzing a theoretical true position of the hole center, then comparing x, y, and z values of our actual hole center. We then use the formula (SQRT(xdev)^2+(ydev)^2+(zdev)^2)x2
To me, this seems like it creates a spherical tolerance zone rather than a cylindrical one. I would have thought we would only calculate the x deviation and y deviation of the hole, because in my mind, the diameter is a 2 dimensional tolerance in which we would measure x and y in relation to the plane the hole is on, then just the axis of the hole has to be good to that plane.
Could you please help me understand this correctly?
I apologize in advance for my basic understanding of things, I've only been in my trade for a few years. I've learned enough to know what I need to make good manufacturing decisions, but I feel that I'm a bit lacking in knowledge regarding inspection.
Here's the situation: I've got a part that I'm not sure my company is inspecting properly, but nobody here is explaining it to me in a way that makes sense with any of the research and learning regarding GD&T that I've done over the past few years. I'm not able to share the actual data or prints, so I've made a mock drawing (isometric view) that mimics the part surfaces, holes, and tolerances.
See the attached pdf - I'm interested particularly in how the nearest hole (position diameter of .003 to datums A, C, D) would be inspected relative to the datum scheme. My understanding of this positional tolerance is as follows:
A theoretical true position is created at the center point of that hole relating back to the established datums.
A cylindrical tolerance zone with a diameter of .006 is created through the material that the hole is in. (This cylindrical tolerance zone would be normal to the face of that surface, or the theoretical angle of that surface relative to the established datums?)
The axis of the hole (actual condition) must fall within that cylindrical tolerance zone.
The way it is being explained to me, we are analyzing a theoretical true position of the hole center, then comparing x, y, and z values of our actual hole center. We then use the formula (SQRT(xdev)^2+(ydev)^2+(zdev)^2)x2
To me, this seems like it creates a spherical tolerance zone rather than a cylindrical one. I would have thought we would only calculate the x deviation and y deviation of the hole, because in my mind, the diameter is a 2 dimensional tolerance in which we would measure x and y in relation to the plane the hole is on, then just the axis of the hole has to be good to that plane.
Could you please help me understand this correctly?