real constants for Beam23

[aminjamali]

I wonder how to define real constants for Beam23 elements when "general section" is under consideration. I couldn't figure out what are those "area at -50 ...". How would you find those values for let's say a W14x132 section?

Thanks for the help

 

[ansysfreak]

Hi

A(-50) = (42*132)*0.0625 = A(50)
A(-30) = (42*132)*0.28935 = A(30)
A(0) = (42*132)*0.2963

Because--> (0.0625*2)+(0.2895*2)+0.2993 = 1

 

[aminjamali]

Hi Ansysfreak

Under section "14.23. BEAM23-2-D Plastic Beam" there are five equations to be solved in order to find input Areas. In case of a W14x132 I get these, I am not sure if I understood the Ansys help properly though:

A(50)=A(-50)=0.974
A(30)=A(-30)=135.949
A(0)=9.4815

I didn't understand where what is "42x132"?

Thanks a lot

 

[ansysfreak]

Hi

The 42 must be 14, sorry.
Note that the area is not used in the computation of the width.

Rectangular
Int Loc Factor H Width
1 -.5 .06250000 12Izz/h^3=width
2 -.3 .28935185 12Izz/h^3=width
3 .0 .29629630 12Izz/h^3=width
4 .3 .28935185 12Izz/h^3=width
5 .5 .06250000 12Izz/h^3=width

Izz = (1/12)* Width * h^3

These values need to be aplied in the R Commando

Explain me?
A(50)=A(-50)=0.974
A(30)=A(-30)=135.949
A(0)=9.4815

 

[aminjamali]

For a W14x132:
A=38.8 in^2
Depth=14.7 in
I (i.e. I2)=1530 in^4

Substitution of these is the equations attached gives:
A(50)=A(-50)=0.974
A(30)=A(-30)=135.949
A(0)=9.4815

Note that we need to guess one of the variables, I guessed A(0) the way Ansys help recommends:
A(0)= depth x web thickness= 14.7 x .645=9.4815

This procedure is what I understood from Ansys help, I wasn't sure if I had a right perception of it though. May be I am totally wrong?