WE17
Materials
- Jul 25, 2013
- 31
Hi Everyone,
I have question regarding Subsize Specimen (Asme VIIITable UG-84.2 ,Asme B31.3 Table 323.3.4, AWS D1.1 Table 4.15 )But for now Just concentration for ASME VIII div 1 Table UG-84.2 and See UG-84(c)(5)(b).
First Question :
1. I have PQR 6 inch, schedule 40 pipe (168.3mm outside diameter x 7.11mm wall thickness)so what is Temperature Reduction and Thickness Reduction ???
By seeing note in Table UG-84.2 note below said : Stright Line Interpolation for intermediate values is permitted ?
SO are you agree if :
a. Temperature Reduction is (by stright line interpolation): ((7-7.11)/(7-7.5)=(4-x)/(4-3)) result is 3.78 deg C
Let say MDMT is -40 deg C so Impact doing in -43.78 deg C ?
or
We need aware of 80% of nominal thk. so calculation max thk I can use 5mm THK so :
THK 5 = 11, THK 7 = 4 means 11-4=7 deg C , Let say MDMT -40 so test temperature -47 deg C ?
b. Thickness Reduction (Let say acceptance criteria 27 Joule) is by stright line interpolation): result is 19.197
so acceptance beeing 19.197 joule instead 27 Joule ?
Please anyone who interesting with this case to help me understanding the interprestation ? Thankyou for valuable advice
we 17
Thanks n Regards
I have question regarding Subsize Specimen (Asme VIIITable UG-84.2 ,Asme B31.3 Table 323.3.4, AWS D1.1 Table 4.15 )But for now Just concentration for ASME VIII div 1 Table UG-84.2 and See UG-84(c)(5)(b).
First Question :
1. I have PQR 6 inch, schedule 40 pipe (168.3mm outside diameter x 7.11mm wall thickness)so what is Temperature Reduction and Thickness Reduction ???
By seeing note in Table UG-84.2 note below said : Stright Line Interpolation for intermediate values is permitted ?
SO are you agree if :
a. Temperature Reduction is (by stright line interpolation): ((7-7.11)/(7-7.5)=(4-x)/(4-3)) result is 3.78 deg C
Let say MDMT is -40 deg C so Impact doing in -43.78 deg C ?
or
We need aware of 80% of nominal thk. so calculation max thk I can use 5mm THK so :
THK 5 = 11, THK 7 = 4 means 11-4=7 deg C , Let say MDMT -40 so test temperature -47 deg C ?
b. Thickness Reduction (Let say acceptance criteria 27 Joule) is by stright line interpolation): result is 19.197
so acceptance beeing 19.197 joule instead 27 Joule ?
Please anyone who interesting with this case to help me understanding the interprestation ? Thankyou for valuable advice
we 17
Thanks n Regards