WRC-537 Calculation

[Champ58]

Hi all,
Do we need to include weld-leg size in calculating 'c1' & 'c2' values (rectangular attachment)?
If I have a rectangular attachment of L=5" and W=3" with a weld-leg size of 0.25". Which one is correct below?

Method-A:
c1 = 3/2 = 1.5"
c2 = 5/2 = 2.5"

Method-B:
c1 = 3/2 + 0.25 = 1.75"
c2 = 5/2 + 0.25 = 2.75"

Similarly, what will be the case in the circular attachment? Does 'Ro' value include weld-leg size?

I have found Codeware-Compress including weld-leg size for rectangular attachment and not using in circular attachment.

I really appreciate any help you can provide.
Thanks

 

[jtseng123]

Don't worry that much. Use method B and round attachment without considering weld size to ease your life. For sure you can add weld to round attachment, but no one cares about it.

 

[JStephen]

If the load assumptions used in the derivation were uniform load over a round or rectangular area, I'd just use the plate size.
If they assumed line loads in a square or circle shape, I'd figure center of throat of weld.
In either case, the design is rather approximate, so there may not be a practical difference.