Quantify the pull force and apply a generous service factor. Come back with a force value, height of winch force above floor level (if you are mounting this to a slab), or some information on what the winch mounts to and you'll probably get better suggestions. Based on not solving the conveyor...
Another thing to consider is using a lower modulus of elasticity material, such as an aluminum structural member. Roughly 1/3 the modulus of steel will provide triple the deflection for similar sections.
If I were looking into it I would start by looking at maximum feeder motor power and assume that Power = Force x Velocity where the velocity is the screw feed rate. There is plenty of literature on screw feeders. Attached is one source. Probably would get some really good advice from the feeder...
Not sure what product you are using but my Simpson LRU series use a short nail or screw and the attachment points are offset on the sides of the rafter to avoid this problem.
Curious if I'm looking at a scarf cut or a weld. There are witness marks on the floor that seem to indicate that there was tubing removed. Not sure what is being shown, asked, etc.
This seems like a miter box gear manufacturer question. What type of bearings are used will have a lot to do with the allowable axial load that this sustains. How much axial load is involved?
amarks - that paper was written before the advances in Ringfeder design and knowledge. I recommend a call and discussion with Ringfeder. They know their products and understand the applications.
Not going to do any of your work, but it looks like you want to make a welded drum where the shaft welds to the end disks. You are probably going about this wrong and are going to replace or repair an expensive drum. Take a look at the attached paper for a little guidance. If you insist on...
Not understanding why you aren't modifying a commercially available product to produce your special crimp. Why are you reinventing the complete method and tooling? It all seems too complicated for no reason.
You need to indicate the force which needs to be developed and the stroke to open and close your crimping dies. At a 30:1 ratio, that is possibly a lot of revolutions of the wheel by an operator. In general, operators do not like to turn a wheel, say, 60 revolutions (each way) to make one part...
You may need to describe, or think through, how to react the torque from a 30:1 handheld contraption - what resists this reaction? Even if it is powered with a portable drill motor, there will be some high handle forces. You need to think it through or describe it better.
Maybe something along...