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Any constructive criticism of my updated design approach? 4

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RodRico

Automotive
Apr 25, 2016
508
All,

I'm now patent pending on my design updates incorporated since filing the original patent, so I can show it now and solicit critique (for those familiar with the system engineering process, the first patent reflected Preliminary Design while the new continuation patent reflects down select of mechanization options to a final design). There are still a number of details to complete, but I estimate final design is about 90% complete at this point.

Folks may recall my engine is a rotating cylinder radial that uses opposed pistons mated to a dedicated charge pump for scavenge/charge and employs a two-stroke Homogeneous Charge Compression Ignition (HCCI) cycle. All pistons are driven by cams, and each set of cylinders completes four full cycles per revolution. With six cylinder sets, the result is 24 complete cycles per revolution. One key difference between the current design and the original is the relocation of the charge pump from its radial position coaxial with the opposed pistons to a new position beside the opposed pistons. This change allows use of a third cam to drive the charge pump piston which previously moved in unison with the outside piston of the opposed pair. This new position shortens the transfer passage between the charge piston and the opposed pair, allows greater flexibility in charge pump timing versus the opposed pair, eliminates the cam shaft (and associated flexure) of the prior design, and maximizes the cam contact area of the heavily loaded pistons of the opposed pair. Combined with a new intake/exhaust port layout, the new approach significantly reduces back pressure (and thus pumping loss) during scavenge/charge. Another key change in the new design is reduction of the innermost piston's stroke to encompass opening and closing the intake port alone while allocating the full compression/expansion stroke to the outer piston of the pair. This change is a simple matter of mechanics; the radius of the inside cam is much smaller than the radius of the outside cam, and the larger radius cams can move further in a given number of degrees and a given material stress limit. The final major difference in the new design is the incorporation of a traditional valve/port controlled version of the Atkinson cycle to mechanize variable compression ratio and control autoignition timing; the inner cam controlling intake port timing is rotated relative to the outer cams so the port remains open during some portion of the compression stroke (note the charge pump cam profile is the inverse of the main piston's cam profile during this period so the net pressure of the Atkinson transfer is near zero). This facility is controlled according to knock sensors in the inner cam as well as atmospheric pressure and temperature sensors to vary compression and ensure ignition occurs at the ideal time in the cycle.

Below is a Solidworks Motion Study animation of one cylinder set (of 6) comprised of an opposed piston pair and a charge pump piston. Note that the animation rotates the cams rather than the pistons and cylinders as in the final design so that the cycle can be better observed. The animation shows the charge pump ports are aligned with the intake ports which are open and closed by the upper (or innermost) piston. Note the circular pocket near the intake ports in the main cylinder; this is where the fuel injectors are installed. Driven by a cam in the side housing, these fuel injectors start injecting at a fixed point in the cycle representing the latest possible closure of the intake port.

Annotated-Long_vgttyt.gif


Per my math and CAD models, the prototype engine will displace between 25 and 31 cc depending on altitude and ambient conditions (25cc on a standard day at sea level). The engine will be 6 inches in diameter and 5 inches thick and employ a bore of just over 1 inch with stroke sweeping a total of 0.481 inches (including the 0.062 inch tall ports at the top and bottom of the cylinder). It will produce 5.7 HP @ 2,626 RPM (propeller speed) and 11.5 lb-ft of torque with 58.6% efficiency including friction and pumping loss (68.3% theoretical) at sea level. 73% of said performance will be available at 15,000 foot altitude (even though air density is only 62.9% of that at sea level). The weight is high at 16.5 lb, but I expect that to come down to around 10-12 lb after weight reduction is complete (deferred until after all other aspects are proven). Performance figures are, of course, subject to validation in real hardware, but I'm encouraged by the 58.6% efficiency indicated by the models; as long as the end result is above 50%, I've got a real product.

Based on threads regarding the Achates engine, I imagine some will be quick to point out that opposed piston engines tend to dump oil out the cylinder ports. Now that the updated patent is filed I can say that this is one area where a rotating cylinder block is key; the passages to and from the intake and exhaust ports will be tilted slightly inward toward the motor axis such that oil exiting the ports can be collected via centrifugal force and routed back into the low pressure oil loop (which flows nearby through passages surrounding each cylinder for cooling). This of course assumes that the oil exiting the ports is in liquid form, and I'll have to conduct experiments to determine how it exits the port and how best to capture it aided by centrifugal force.

The whole point of this post is to solicit constructive criticism, so don't hold back. I only ask that it be constructive and respectful.

Rod
 
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What are all the reciprocating parts made of? And piston follower guide material? Any pressure lube to any parts?
 
hemi said:
That's why it's best to stick with conventional measures for comparing engines, i.e. BMEP and power density. Lest you confuse us old curmudgeoneers.

Here you go. The equation deriving BMEP shown in blue is from EPI Inc's wonderful web site. Note that "PPR" is Power Pulses per Revolution which relates to the engine type (4 stroke PPR = 0.5, 2 Stroke = 1, Mine = 4).

Capture2_dpl7vq.jpg


enginesrus said:
What are all the reciprocating parts made of? And piston follower guide material? Any pressure lube to any parts?

All recipricating components as well as the cylinder liners, cams, and piston guides are designed assuming use of aged Maraging 350 steel. The main bearings are deep groove roller bearings, all other friction is sliding. Cam surface speeds are high, so I expect them to be in the hydrodynamic regime. The piston guides (essentially piston skirts) and ring pack are similar to a traditional engine. Other then the pressure developed by hydrodynamic operation of the cams, all lubrication is low pressure.
 
To be clear, displacement needs to be figured as swept volume per revolution. Is that what you did?

"Schiefgehen wird, was schiefgehen kann" - das Murphygesetz
 
hemi said:
To be clear, displacement needs to be figured as swept volume per revolution. Is that what you did?

Look at the denominator of the equation below the table. My engine's Power Pulses per Revolution (PPR) is 4 while that of the others is only 0.5 (4 stroke) or 1 (2 stroke).
 
Doesn't answer my question. What is the swept volume per revolution?

"Schiefgehen wird, was schiefgehen kann" - das Murphygesetz
 
hemi said:
Doesn't answer my question. What is the swept volume per revolution?

I did answer your question by showing that the swept volume per revolution is inherent to the term "Displacement x PPR" in the BMEP equation. If you're interested, each cylinder displaces 4.17 cc and there are six, so the combined displacement is 25cc. These cylinders complete four cycles per revolution of the output shaft which turns at 2,626 RPM max. As I learned from gruntguru some time back, I could just as easily say my engine is a two-stroke with one quarter the torque operating at 10,504 RPM with a 4:1 reduction gear on the output shaft. Based on my cam loading analysis, I could in fact design the engine to have one power stroke per revolution and operate at 10,504 RPM, but then I'd need a 4:1 reduction gear to bring the shaft speed down to that associated with efficient propellers. Thus, the four power strokes per revolution is simply a more efficient way to mechanize a 4:1 reduction gear.
 
If one cylinder displaces 4.17 cc in 1 up and down cycle, there are 6 of these cylinders, and there are 4 up-down cycles per revolution, then your swept volume per revolution is 100cc. With that swept volume per revolution I get BMEP=36.4
To be clear, only power producing cylinders should be counted in the swept volume. Are we on the same page there?



"Schiefgehen wird, was schiefgehen kann" - das Murphygesetz
 
hemi said:
Are we on the same page there?

No.

From the "Derivation of the BMEP Equations" at the bottom of the page at BMEP = (Torque * 12 * 33,000/5252)/(displacement * PPR) where BMEP is in psi, Torque is in lb-ft, displacement is in in^3, and PPR is the number of power pulses per revolution.

Your "up-down cycles per revolution" language is already inherent to the denominator of the equation in the form of power pulses per revolution.

The displacement of the engine is 1.526 ci and the engine creates four power pulses per revolution, so the denominator of the BPEM equation is 6.104 (your 100cc).
The torque of my engine is 11.563 lb-ft so the numerator of the equation is 11.563 * 12 * 33,000/5252 or 871.848, so BMEP = 871.848/6.104 or 142.8 psi.

If you insist my displacement is 100cc (1.526 in^3), you should use the equations at the bottom of the "Derivation of the BMEP Equations" section.
For a two-stroke engine the equation is BMEP = 75.4 * Torque / Displacement. Plugging in my numbers, BMEP = 75.4 * Torque/Displacement = 75.4 * 11.563 / 1.526 = 142.8 psi.

I've posted my equations and their reference source. Please post your equations and reference source so we can compare.

P.S. Note my thermodynamic model calculates Work, IMEP, FMEP, and BMEP from the bottom up then calculates HP and Torque. If you want to go that route, the key figures for one cycle of one cylinder at 2,626 RPM are Work = 4.3 Joules, Displacement = 4.17E-06 m^3, IMEP = 10.4 bar, FMEP = 0.53 Bar, and the engine completes 24 full cycles per revolution.
 
In one revolution, how much volume does your engine displace?

"Schiefgehen wird, was schiefgehen kann" - das Murphygesetz
 
hemi said:
In one revolution, how much volume does your engine displace?

That's not the standard definition used when labeling an engine's displacement. Most folks just take the swept+clearance volume of one cylinder and mutiply it by the number of cylinders. This is evident in how we calculate the displacement of two-stroke and four-stroke engines; two engines of the same bore, stroke, and clearence volume are labeled as having the same displacement even if one of them is two-stroke and the other is a four-stroke. This in spite of the fact the two-stroke processes twice as much air through combustion every revolution as a four-stroke.

By the standard convention relating Power Strokes per Revolution (PPR) to the stroke class of an engine (Stroke Class = 2/PPR), mine happens to be "half-stroke." It shouldn't be penalized relative to a two-stroke by quadrupling its displacement any more than a two-stroke is penalized relative to a four-stroke by doubling its displacement. For reference, here are the standard equations showing the relation between stroke-class and Power Pulses per Revolution (PPR) in BMEP calculations:

[pre]Generic BMEP = (Torque x 12 x 33,000 / 5252) / (Displacement x PPR)
4.0-Stroke BMEP = (Torque x 12 x 33,000 / 5252) / (Displacement x 0.5) = 150.80 x Torque/Displacement
2.0-Stroke BMEP = (Torque x 12 x 33,000 / 5252) / (Displacement x 1.0) = 75.40 x Torque/Displacement
0.5-Stroke BMEP = (Torque x 12 x 33,000 / 5252) / (Displacement x 4.0) = 18.85 x Torque/Displacement
[/pre]
Another perspective is that my engine processes the same volume of air per unit of time through combustion as a 50cc two-stroke running at 10,504 RPM. Nobody drives a car wheel or weed whacker at 10,504 RPM, they employ some form of speed reduction between the engine and the working shaft. My engine just happens to have a clever 4:1 reduction facility integral to the design. This perspective is bolstered by my piston speed; each power stroke completes in only 23.6 degrees of output shaft rotation.

All of the above is symantics, so one could ask why I care. Simple. Many countries and states limit moped displacement to 50cc. Doubling the displacement of a two-stroke because it processes twice as much air through combustion as a four stroke every revolution would severely limit the attractiveness of two-stroke moped engines. Likewise, quadrupling the displacement of my engine because it processes four times as much air per revolution as a two-stroke would limit the attractiveness of my engine. There are similar displacement rules establishing different classes of engines for emissions requirements. It does matter.

Determining the legal displacement of engines that don't use a crankshaft has been painful in the past (some of us no doubt recall the debate regarding the displacement of Mazda's Wankels). Setting the above semantics of displacement aside, my real concern is that you came up with an absurdly low figure for BMEP (36.4 psi) relative to mine (142 psi). I've asked you to post your equations and references so I can compare, but you've yet to do so.
 
(11.6*12*33,000/5252)/(6*4) = 36.4

"Schiefgehen wird, was schiefgehen kann" - das Murphygesetz
 
BMEP aside, I can't recall that you ever showed us a PV diagram. Do you have one?

"Schiefgehen wird, was schiefgehen kann" - das Murphygesetz
 
hemi said:
(11.6*12*33,000/5252)/(6*4) = 36.4

You've double-booked a factor of four in the denominator.
The displacement of my engine independent of PPR is 25cc. You made it 100cc by multiplying by PPR, so you don't need to multiply by PPR a second time.
[pre]
If you want to use the 100cc perspective, then displacement is 6.10 in^3 and PPR is 1, so the denominator should be (6.10*1)
If you want to use the 25cc perspective, then displacement is 1.53 in^3 and PPR is 4, so the denominator should be (1.53*4)
[/pre]
Both denominators are the same and yield the same BMEP, but saying my engine has only one Power Pulse per Revolution is incorrect. It has four.

I'll plot PV tomorrow.
 
To me, and now with the benefit of seeing the animation, the idealised PV diagram will look like that of an idealised two-stroke Otto cycle. (Constant-volume combustion at the moment of minimum volume.) Of course, the real-world combustion process will differ from the ideal. Scavenging, in the ideal cycle, happens at constant (atmospheric) pressure. Of course, there will be pressure losses in real-world operation.
 
Here are plots of cam profiles as well as the PV diagram of one opposed piston pair at sea level with Atkinson mode active (displacement|compression ratio reduced from max 31cc|36:1 to 25cc|29:1 via late intake port closure). Several attributes of the cam and port timing are worthy of description. Note that scavenge starts and ends with both the exhaust and intake ports wide open (no gas transfer with partial port openings), and the full volume of air is replaced at atmospheric pressure. Compression doesn't start until the intake port closes a little late in this case which indicates the Atkinson mode is active. After compression, the cylinder is held at minimum volume for a short while to allow completion of the rapid HCCI combustion event at constant volume. Combustion gasses are then expanded at a constant ratio of 1:36. Next, the exhaust port opens to start blow-down. Once blow-down completes, the intake port opens and the cycle begins anew.

Capture5_gbwigq.jpg


The primary purpose of the Atkinson mode is to allow control over compression ratio which is modified according to ambient air temperature and pressure to improve performance at altitude and provide the extra compression needed for cold start at sea level. The variable compression capability is also used to control autoignition timing informed by knock sensors. Atkinson operation is controlled by modifying intake port closure timing relative to exhaust port closure at the start of compression. This is accomplished by rotating the inner cam relative to the outer cam using a servo.

Note the PV plot does not include the Charge Pump because it's a bit confusing when put on the same plot as the opposed piston PV. The volume of the charge pump and the main cylinder ranges from 2x the main cylinder volume plus manifold volume down to 1x the main cylinder plus manifold volume. The cylinders have 0.56 cm^2 of port area servicing 5.2 cc of cylinder volume and gas transport during scavenge/charge is rate controlled by design to yield no more than 0.1 bar back pressure/vaccum.
 
RodRico said:
You've double-booked a factor of four in the denominator.
The displacement of my engine independent of PPR is 25cc. You made it 100cc by multiplying by PPR, so you don't need to multiply by PPR a second time.
I stand corrected. The 4 lobe cam had me barking up the wrong tree.

What IMEP do you get from your PV curve?

"Schiefgehen wird, was schiefgehen kann" - das Murphygesetz
 
Dwell at TDC would be unnecessary under HCCI (very rapid combustion) conditions and is undesirable due to increased heat loss. Also there are difficulties reducing the high "jerk" arising from a "flat topped" velocity profile for the piston.

It appears that you no longer expect the secondary piston motion to initiate HCCI - congrats.

Using secondary piston phasing to vary CR is a strong feature of your design.

je suis charlie
 
I'm no expert on cam profiles, but unless I'm missing something the ramp accelerations look pretty severe. What's the story?

"Schiefgehen wird, was schiefgehen kann" - das Murphygesetz
 
Probably OK while it is still "on paper". Just investigating gas exchange and thermodynamics.

je suis charlie
 
hemi said:
What IMEP do you get from your PV curve?
For one cylinder executing one cycle, displacement = 4.167E-06 m^3, work = 4.32 J, IMEP = 10.38 bar, FMEP = 0.53 bar, and BMEP = 9.85 bar.

gruntguru said:
Dwell at TDC would be unnecessary under HCCI (very rapid combustion) conditions and is undesirable due to increased heat loss.
The time duration of the flat at max RPM is equal to the fuel's ignition delay at the peak compression temperature. The knock sensors and variable CR will be used to position the combustion event at the end of the flat where expansion begins so heat and pressure loss are minimized. Setting the flat to full ignition delay may be overly conservative. I will adjust or eliminate the flat based on measured data during testing.

gruntguru said:
There are difficulties reducing the high "jerk" arising from a "flat topped" velocity profile for the piston.
True, but it has to stay until I know I don't need it.

gruntguru said:
Using secondary piston phasing to vary CR is a strong feature of your design.
I agree. Other features highlighted in the patent include near uniform cylinder temperature due to the radial cylinder arrangement (eliminating the "cold" cylinders at the ends of an inline or V arrangement that wreck havoc on HCCI control), the integration of a 4:1 propeller reduction gear via four cycles per revolution, the "free" and highly reliable oil/cooling pump provided by the spinning rotor, and use of centrifugal force to recover oil scraped into the ports.

hemi said:
The ramp accelerations look pretty severe. What's the story?
The plots I provided didn't show the cam profile (which defines acceleration and minimum follower radius), they showed piston lift resulting from the combined effect of the cam profile and follower pressure angle (which is useful for visualizing port timing). In the plots below, you can see how the piston lift plot tends to sharpen some transitions and soften others compared to the naked cam profile. Regardless, both plots show high acceleration. My compression ratio at sea level standard conditions is 29:1 which is much higher than normal for an HCCI engine and is only possible because I get through the compression stroke faster than the fuel's ignition delay even at minimum RPM. Rapid stroke is also desireable on both compression and expansion to minimize blow-by and heat transfer. Note the pump piston's acceleration is the highest of the three, but that piston is never subjected to compression or combustion, is significantly lighter, and thus has less cam stress even at higher acceleration. Ultimately, the limit is defined by material yield limits, and all cams operate with significant margin.

Capture6_nikkdu.jpg
 
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