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Partially filled head volume
- Thread starter Bearcat
- Start date
I went through my reference books and even managed to dig out (after finding it) some old engineering documents I hoped might have it with no success. Horizontal, yes. Vertical, no.
However, the GPSA data book has a tabular set of data for the fractional volume of a vertical head at different liquid depths. You might want to try curve fitting a set of data points depending on the accuracy you need.
However, the GPSA data book has a tabular set of data for the fractional volume of a vertical head at different liquid depths. You might want to try curve fitting a set of data points depending on the accuracy you need.
- Thread starter
- #4
Thanks for the replies. For anyone who may need similar information, I got the following formulas from Chicago Bridge & Iron Co bulletin #594, page 7:
Volume or contents of partially filled hemi-ellipsoidal heads with major axis vertical
Q= Partially filled volume or contents in ft^3
V= Total volume of one head in ft^3
R= Radius of cylinder in ft
delta= a/(KR) where
a= liquid height
KR= head height
Upper head Q=1.5*V*(delta)*(1-(1/3*(delta)^2))
Lower head Q=1.5*V*(delta)^2*(1-(1/3*(delta))
It probably gives you the same result as the one refrenced above by mgp.
Unfortunately I was unable to find a formula for an ASME F&D head but I was able to fit a equation to curvature of tank in question. Using this, I can find the volume of a solid of revolution bound between the curve and a horizontal line at the liquid level. Kind of long but I think it will work close enough.
Once again thanks for effort TD2K and mgp.
Chris
Volume or contents of partially filled hemi-ellipsoidal heads with major axis vertical
Q= Partially filled volume or contents in ft^3
V= Total volume of one head in ft^3
R= Radius of cylinder in ft
delta= a/(KR) where
a= liquid height
KR= head height
Upper head Q=1.5*V*(delta)*(1-(1/3*(delta)^2))
Lower head Q=1.5*V*(delta)^2*(1-(1/3*(delta))
It probably gives you the same result as the one refrenced above by mgp.
Unfortunately I was unable to find a formula for an ASME F&D head but I was able to fit a equation to curvature of tank in question. Using this, I can find the volume of a solid of revolution bound between the curve and a horizontal line at the liquid level. Kind of long but I think it will work close enough.
Once again thanks for effort TD2K and mgp.
Chris
Check the reference
"Calculating Tank Volume" by Tim Broyles - Chemical Processing 2000 Fluid Flow Annual p.32
"Calculating Tank Volume" by Tim Broyles - Chemical Processing 2000 Fluid Flow Annual p.32
DeltaCascade
Chemical
Gone are the days of everyone having the time to use second year university calculus and deriving the formulas from scratch by adding a couple of relatively simple integrals and solving for equation... I must be just too sentimental ... 
Hey Delta, I don't know if those days are gone, or not. Last year I had to calculate the volume of a weir mounted up on the wall inside a vertical vessel. The weir was open at the top and trapeziodally-shaped in section. I had to calculate the volume (this was a skim trough in an IGF flotation cell) because the dump valve worked on a timer and we didn't want to blow a bunch of gas thru the dump valve and into the system. So I set up a double integral, roated it thru 2pi, and it worked. My old calc prof would have been proud. I even did it in the field, in the control room, in the rain, during a startup! How 'bout that! ;-) Thanks!
Pete
P. J. (Pete) Chandler, PE
Principal Engineer
Mechanical, Piping, Thermal, Hydraulics
Processes Unlimited International, Inc.
Bakersfield, California USA
pjchandl@prou.com
Pete
P. J. (Pete) Chandler, PE
Principal Engineer
Mechanical, Piping, Thermal, Hydraulics
Processes Unlimited International, Inc.
Bakersfield, California USA
pjchandl@prou.com
The software cerebrotank give the exact parcial volume of vertical and horizontal tanks with any head commonly used.
Get a demo version in
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